op-assign in function argument
has anybody thought the op-assign in function argument is a good idea? now we can use parameter name to specifie argument, like this:
def foo(arg1): pass
# call foo(arg1 = "bar")
but, if function has default parameter, it will be inconvenience: def foo_with_long_defualts(arg1 = we | are | default | flags | set): pass
# call foo_with_long_defaults(arg1 = we | are | default | flags | set | another_flags)
so, why not add op-assign support in named argument?
foo_with_long_defaults(arg1 |= another_flags)
are there anybody has the same idea with me?
On Wed, Feb 24, 2010 at 1:23 AM, wxyarv weasley_wx@qq.com wrote:
has anybody thought the op-assign in function argument is a good idea? now we can use parameter name to specifie argument, like this:
def foo(arg1): pass
# call foo(arg1 = "bar")
but, if function has default parameter, it will be inconvenience: def foo_with_long_defualts(arg1 = we | are | default | flags | set): pass
# call foo_with_long_defaults(arg1 = we | are | default | flags | set | another_flags)
so, why not add op-assign support in named argument?
foo_with_long_defaults(arg1 |= another_flags)
If you wan to do this, you can just support it in the function yourself. That is, if the function wants to take an additional_flags parameter, it should. I don't think the complications this could add to the call syntax are good. It becomes a form of assignment-as-an-expression and makes the call harder to parse (by human eyes).
are there anybody has the same idea with me?
-1
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Calvin Spealman wrote:
On Wed, Feb 24, 2010 at 1:23 AM, wxyarv weasley_wx@qq.com wrote:
has anybody thought the op-assign in function argument is a good idea? now we can use parameter name to specifie argument, like this:
def foo(arg1): pass
# call foo(arg1 = "bar")
but, if function has default parameter, it will be inconvenience: def foo_with_long_defualts(arg1 = we | are | default | flags | set): pass
# call foo_with_long_defaults(arg1 = we | are | default | flags | set | another_flags)
so, why not add op-assign support in named argument?
foo_with_long_defaults(arg1 |= another_flags)
If you wan to do this, you can just support it in the function yourself. That is, if the function wants to take an additional_flags parameter, it should. I don't think the complications this could add to the call syntax are good. It becomes a form of assignment-as-an-expression and makes the call harder to parse (by human eyes).
Even better is to just give the default args a name:
FOO_DEFAULTS = we | are | default | flags | set def foo(arg=FOO_DEFAULTS): ...
my_flags = FOO_DEFAULTS | other_flags foo(arg=my_flags)
(Also -1 on this syntax idea - simply giving the default value a name is a much simpler and more obvious approach)
Cheers, Nick.
participants (3)
-
Calvin Spealman -
Nick Coghlan -
wxyarv