Team,
Are we supposed to be able to have our own class dictionary in python 3?
If we currently cannot -- do we want to be able to?
That we can have out own class dictionary in python 3 is strongly implied
in the following at https://www.python.org/dev/peps/pep-3115/ where it
says:
"""
# The metaclass invocation
def __new__(cls, name, bases, classdict):
# Note that we replace the classdict with a regular
# dict before passing it to the superclass, so that we
# don't continue to record member names after the class
# has been created.
result = type.__new__(cls, name, bases, dict(classdict))
result.member_names = classdict.member_names
return result
"""
I don't understand this. As far as I can tell, no matter what class
dictionary you pass into `type.__new__` it creates a copy of it.
Am I missing something? Is this supposed to work? Is the documentation
wrong?
Thanks,
Joy Diamond.
Program that shows that the class dictionary created is not what we pass
in --- Shows the actual symbol table is `dict` not `SymbolTable`
class SymbolTable(dict):
pass
members = SymbolTable(a = 1)
X = type('X', ((object,)), members)
members['b'] = 2
print('X.a: {}'.format(X.a))
try:
print('X.b: {}'.format(X.b))
except AttributeError as e:
print('X.b: does not exist')
#
# Get the actual symbol table of `X`, bypassing the mapping proxy.
#
X__symbol_table = __import__('gc').get_referents(X.__dict__)[0]
print('The type of the actual symbol table of X is: {} with keys:
{}'.format(
type(X__symbol_table),
X__symbol_table.keys()))
# Prints out
# X.a: 1
# X.b: does not exist
# The type of the actual symbol table of X is: <class 'dict'> with keys:
dict_keys(['a', '__module__', '__dict__', '__weakref__', '__doc__'])
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