Hi,

Hi,

I'm new; greetings all!

I'm not sure if this is a bug or feature, but it confused me so I thought I'd raise the issue.

class a: def b (self): pass

foo = ('Hello', b)

class c(a): def d(self): t = type (self. __class__. foo [1]) print t t = type (self. __class__. b) print t

e = c () e. d()

prints <type 'function'> for the first print, and it seems to me it should be an instancemethod

[snip] I think what's happening is that it's defining 'b' as a function in the class's namespace, storing a reference to that function in the tuple, and then, when the class definition ends, it's wrapping the function as a method.

You'll find:

...

...

...

a.foo[1] <function b at 0x00B42C30> a.b <unbound method a.b> a.b.im_func is a.foo[1] True

I'm afraid this won't do what I want. As illustrated below, I want to store the reference from withing the same class, so as to be able to access in from a superclass. (sorry if subclass and superclass is not the correct terminology for Python)

I'm trying to something like this

class EditPage:

additonal_buttons = () def __init__ (self): buts = [] for x in addional_butons: if isinstance (x [1], types. UnboundMethodType): # fails because type (x [1]) is function, not UnboundMethod buts. append ((x [0], types. MethodType (x [1], self))) else: buts. append (x)

class TreePage(EditPage): def EditAsText (self): pass

additional_buttons = (('EditAsText', EditAsText),)

It might be that Python simple doesn't do exactly what I want. This is really unusual; mostly I think it's great and highly intuitive. No biggie; I'm sure I can find a workaround! Bob