Hi Jacob I really like your previous post. I find it really helps me understand what you want. You wrote

I wanted the called, jumped to function to change state in the caller. From what I tried to do, passing locals() cannot accomplish this. I have made it happen in other languages though. In the R language, one can do this

foo = function(){ localenv = environment() eval(bar, environment = localenv)

The above code captures the environment of the calling function and executes the called function as if the calling function's local environment was the global environment.

So in a nutshell, you'd like to be able to write code like this, but in Python?

bar doesn't have to be a function, it can be any valid R expression captured with the expr() function, and everything in R is an expression thus allowing for the full usage code blocks.

This Python can already do. Any Python expression can be turned into a function, simply by prefixing it with 'lambda:'.

Outside of lisp-like languages this feat seems to usually be impossible though.

I'm an Emacs user, so I know Lisp. But R is new to me. But this URL tells me that R is based on Lisp. https://www.i-programmer.info/programming/other-languages/1706-a-programmers... And, in my view, this makes your problem immediately much more important for the Python community. Because both Python and R are major languages in the area of Data Science. Thank you so much for your previous post, and to all the others whose posts have contributed to this clarification. -- best regards Jonathan

Hi Jacob I really like your previous post. I find it really helps me understand what you want. You wrote

I wanted the called, jumped to function to change state in the caller. From what I tried to do, passing locals() cannot accomplish this. I have made it happen in other languages though. In the R language, one can do this

foo = function(){ localenv = environment() eval(bar, environment = localenv)

The above code captures the environment of the calling function and executes the called function as if the calling function's local environment was the global environment.

So in a nutshell, you'd like to be able to write code like this, but in Python?

bar doesn't have to be a function, it can be any valid R expression captured with the expr() function, and everything in R is an expression thus allowing for the full usage code blocks.

This Python can already do. Any Python expression can be turned into a function, simply by prefixing it with 'lambda:'.

Outside of lisp-like languages this feat seems to usually be impossible though.

I'm an Emacs user, so I know Lisp. But R is new to me. But this URL tells me that R is based on Lisp. https://www.i-programmer.info/programming/other-languages/1706-a-programmers... And, in my view, this makes your problem immediately much more important for the Python community. Because both Python and R are major languages in the area of Data Science. Thank you so much for your previous post, and to all the others whose posts have contributed to this clarification. -- best regards Jonathan