Issue #6 Update (Resolve) "Hang caused by multithreaded program that invokes .NET CLR" Status Resolved, Threading/bug critical To followup, visit: http://www.zope.org/Members/Brian/PythonNet/Collector/6
============================================================== = Resolve - Entry #2 by Brian on Mar 31, 2005 9:54 am
Status: Pending => Resolved
This issue is resolved in beta 5 - thanks for the test case (I put a condensed version of it into the unit tests).
-BL ________________________________________ = Request - Entry #1 by Anonymous User on Mar 25, 2005 1:04 pm
Hang caused by multithreaded program accessing CLR methods.
I successfully reproduced the state with a very simple application. Here is very dumb python program that uses the CLR:
from CLR.System import String
class cSharpCaller( object ): def __init__( self ): print "Created a cSharpCaller instance" self.__cSharpString = None
def createCSharpString( self, str ): self.__cSharpString = String( str )
def returnCSharpString( self ): return self.__cSharpString.ToString()
And if I test this with this (dumb) threethreaded testprogram:
import threading, thread, time
from cSharpCaller import cSharpCaller
def start_threads(amount=5): for i in range(amount): thread = threading.Thread(target=process_thread ) print "starting thread ", thread.getName() thread.start()
def process_thread( ): print "thread started " for i in range( 2 ): print "Hi, I'm a thread" time.sleep( 1 ) cs = cSharpCaller( ) cs.createCSharpString( "created from a thread" ) print "cs.returnCSharpString() = ", cs.returnCSharpString() print "thread %s ended"
start_threads( 3 )
I get this output:
starting thread thread0 thread started Hi, I'm thread %s starting thread thread1 thread started Hi, I'm thread %s starting thread thread2 thread started Hi, I'm thread %s Hi, I'm thread %s Hi, I'm thread %s Hi, I'm thread %s Created a cSharpCaller instance Created a cSharpCaller instance cs.returnCSharpString() =
and I have to CTRL+Pause to get out of the hang. Clearly hangs on the first String.ToString() method call.