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5 Aug
2009
5 Aug
'09
1:01 p.m.
--- On Wed, 8/5/09, Robert Kern <robert.kern@gmail.com> wrote:
It is necessarily == D. Broadcasting is associative.
Ah, that's the key I didn't understand! That helps (me) a lot; I'm going to make a "Note" of it in numpy.broadcast's docstring. DG
The (x*y*z).shape == (x*(y*z)).shape == ((x*y)*z).shape.
-- Robert Kern
"I have come to believe that the whole world is an enigma, a harmless enigma that is made terrible by our own mad attempt to interpret it as though it had an underlying truth." -- Umberto Eco _______________________________________________ Scipy-dev mailing list Scipy-dev@scipy.org http://mail.scipy.org/mailman/listinfo/scipy-dev