License compatibility SciPy -> MIT -> GPL
Well, we've been discussion the license combatility for the cubature module.
From the links @Warren gave me: http://wiki.scipy.org/License_Compatibility http://matplotlib.org/devel/license.html#license-discussion
it states that the MIT license is compatible with SciPy, and in the MIT description in Wikipedia (http://en.wikipedia.org/wiki/MIT_License) it states that this license is compatible with the GPL. So... is there a crack here where we could place a GPL software in SciPy? Thank you, Saullo
Hi Unfortunately, it is the other way around: you can put bsd code in gpl code, but if you put gpl code into bsd code, the latter has to be relicensed. Btw, if you put gpl code indide mit code, the same has to be done. Cheers Le 25 août 2013 08:00, "Saullo Castro" <saullogiovani@gmail.com> a écrit :
Well, we've been discussion the license combatility for the cubature module.
From the links @Warren gave me: http://wiki.scipy.org/License_Compatibility http://matplotlib.org/devel/license.html#license-discussion
it states that the MIT license is compatible with SciPy, and in the MIT description in Wikipedia (http://en.wikipedia.org/wiki/MIT_License) it states that this license is compatible with the GPL. So... is there a crack here where we could place a GPL software in SciPy?
Thank you, Saullo
_______________________________________________ SciPy-Dev mailing list SciPy-Dev@scipy.org http://mail.scipy.org/mailman/listinfo/scipy-dev
On Sun, Aug 25, 2013 at 9:00 AM, Saullo Castro <saullogiovani@gmail.com> wrote:
Well, we've been discussion the license combatility for the cubature
module.
From the links @Warren gave me: http://wiki.scipy.org/License_Compatibility http://matplotlib.org/devel/license.html#license-discussion
it states that the MIT license is compatible with SciPy, and in the MIT
description in Wikipedia (http://en.wikipedia.org/wiki/MIT_License) it states that this license is compatible with the GPL. So... is there a crack here where we could place a GPL software in SciPy? No. License compatibility is not commutative. A license is GPL-compatible if it adds no restrictions above those in the GPL. A license is BSD-compatible (and thus scipy-compatible) if it adds no restrictions above those in the BSD license. The GPL adds restrictions above those in the BSD license. We have decided as a matter of policy for the scipy project to only include code that does not add more restrictions than roughly that of the BSD license. This isn't really an issue of license compatibility. You can combine BSD scipy code and GPL code just fine, but we have a policy against including GPL code into scipy because we want to keep the licensing situation simple and understandable and not copylefted. If some scipy packages were BSD-licensed and some were GPL-licensed, everyone will have to pay close attention to which ones they were using to be sure that they are obeying the terms of the GPL license. That's really annoying. It is much easier for everyone involved to keep the GPL code in an entirely separate package. I appreciate your effort in learning about these issues, but please consider it an exercise in personal education rather than trying to find a workaround to include GPL code in scipy. There isn't one. -- Robert Kern
participants (3)
-
Matthieu Brucher -
Robert Kern -
Saullo Castro