This works fine: In [49]: numpy.zeros((3,2))+numpy.array([1,2]) Out[49]: array([[ 1., 2.], [ 1., 2.], [ 1., 2.]]) but this doesn't: In [50]: numpy.zeros((3,2))+numpy.array([1,2,3]) --------------------------------------------------------------------------- ValueError Traceback (most recent call last) C:\Dev\MyProjects\Bio\Python\site_dpm\<ipython console> in <module>() ValueError: shape mismatch: objects cannot be broadcast to a single shape
<ipython console>(1)<module>()
what is the simplest way to get this addition to work? I would like the following array([[ 0., 0.], [ 0., 0.], [ 0., 0.]]) + array([1,2,3]) = array([[ 1., 1.], [ 2., 2.], [ 3., 3.]]) In general my arrays are held in variables and are not constructed on the fly so while this works numpy.zeros((3,2)).T+numpy.array([1,2,3]) which works fine with the '+' operator but not with '+='. This doesn't work: In [54]: a=zeros((3,2)) In [55]: a.T += numpy.array([1,2,3]) --------------------------------------------------------------------------- AttributeError Traceback (most recent call last) C:\Dev\MyProjects\Bio\Python\site_dpm\<ipython console> in <module>() AttributeError: attribute 'T' of 'numpy.ndarray' objects is not writable
<ipython console>(1)<module>()
My guess is that I should do a = (a.T + numpy.array([1,2,3])).T but I wonder if there is a more efficient way. Am I missing something? Thanks, John.