Elmar:

You could use smth like this....

import itertools as itt

import numpy as np

def foo(ncol=1, start=0, end=10, delta=0.1):
    if ncol==1:
        return np.arange(start, end, delta)
    else:
        ranges = ncol * [np.arange(start, end, delta), ]
        for z in itt.product(*ranges):
            yield z

for (x1, x2) in foo(ncol=2):

print(x1, x2)

This is not exactly what you need but might help.

Cheers

2015-11-11 14:17 GMT-05:00 elmar werling <elmar@net4werling.de>:

with the following pattern

the pattern is

0 100 0
0 0 100
10 90 0
10 80 10
10 70 20
10 60 30
10 50 40
10 40 50
10 30 60
10 20 70
10 10 80
10 0 90
20 80 0
20 70 10
20 60 20
20 50 30
20 40 40
20 30 50
20 20 60
20 10 70
20 0 80
30 70 0
30 60 10
30 50 20
30 40 30
30 30 40
30 20 50
30 10 60
30 0 70
... ... ...

On 11.11.2015 19:44, Max Shron wrote:

Can you specify a little more clearly what you're looking for? I'm not
seeing the pattern.

On Wed, Nov 11, 2015 at 1:12 PM, elmar werling <elmar@net4werling.de
<mailto:elmar@net4werling.de>> wrote:

Hi,

is there a function foo(ncols, min, max, delta) in mumpy/scipy to
create an array such as

0 100 0
0 0 100
10 90 0
10 80 10
10 70 20
10 60 30
10 50 40
10 40 50
10 30 60
20 20 70
20 10 80
20 0 90
20 80 0
... ... ...
90 10 0
90 0 10
100 0 0

Any help or link is welcome

Elmar

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Sasha