Hi Nils, It's not a one-liner, but it may serve you: In [40]: n = 4 In [41]: i = 2 In [42]: In [42]: A = arange(n*n).reshape(n,n) In [43]: A Out[43]: array([[ 0, 1, 2, 3], [ 4, 5, 6, 7], [ 8, 9, 10, 11], [12, 13, 14, 15]]) In [44]: I = range(n) In [45]: I.remove(i) In [46]: B = A[ix_(I,I)] In [47]: B Out[47]: array([[ 0, 1, 3], [ 4, 5, 7], [12, 13, 15]]) Cheers, Joris On Wednesday 14 February 2007 09:02, Nils Wagner wrote:

Hi,

I would like to remove the i-th column and row from a two-dimensional array A. The remaining array should be kept and stored in B

A = random.rand(n,n)

This task is very easy if i is the first or last row/column. In that case one can use

B = A[1:,1:]

or

B=A[:-1,:-1]

But, what is the best way to get B if 0 < i < n-1 ?

Nils

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