Mailman 3 September 2011 - Tkinter-discuss

回复： get root.winfo_pointerxy()
by 守株待兔 Sept. 2, 2011

Sept. 2, 2011

in my program,myprint is: def myprint(arg): x=arg.x y=arg.y canvas.create_text(x,y,text='i am here') canvas.bind("<Button-1>",myprint) now ,when i left click mouse on the point in then canvas first time, there is output: i am here when i left click mouse on the point in then canvas second time,there is output too:i am here what i want to get is : when i left click mouse on the point in then canvas second time,the old output (i am here) disappear, only new output (i am here) in the canvas,how to do ? any advice appreciated. ------------------ 原始邮件 ------------------ 发件人: "Cameron Laird"<Cameron(a)phaseit.net>; 发送时间: 2011年9月1日(星期四) 晚上11:19 收件人: "Douglas S. Blank"<dblank(a)cs.brynmawr.edu>; 抄送: "tkinter-discuss"<tkinter-discuss(a)python.org>; 主题: Re: [Tkinter-discuss] get root.winfo_pointerxy() On Thu, Sep 01, 2011 at 10:37:31AM -0400, Douglas S. Blank wrote: . . . > On 09/01/2011 10:21 AM, wrote: > >def myprint(): > > print root.winfo_pointerxy() > > > >canvas.bind("<Button-1>",myprint) > > When you bind a function to the canvas, it is expecting a function that > takes an argument (which is probably the object to which the binding is > bound). > > So, you could just allow myprint to take an argument, and ignore it: > > def myprint(arg): > print root.winfo_pointerxy() . . . I entirely agree with the counsel Dr. Blank has provided. While I expect the original questioner has all he needs to move forward, I'll provide a bit more detail for the benefit of other readers. Let's look at "arg", "which is probably the object to which the binding is bound". It's not; it's the detected *event* (from which that object can be calculated, though) <URL: http://www.pythonware.com/library/tkinter/introduction/events-and-bindings.… >. That's not all. One could temporarily update myprint's definition to be something like def myprint(arg): print "arg is '%s'." % arg print dir(arg) print root.winfo_pointerxy() to have Python's introspection report more information about the argument. And *that* isn't all, either. If one were somehow stranded-on-a-desert-island and unsure how many (not- necessarily-named) arguments were arriving, one could experiment with def myprint(*kw): print kw ...

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回复： get root.winfo_pointerxy()
by 守株待兔 Sept. 2, 2011

Sept. 2, 2011

def myprint(arg): print "arg.x" , arg.x,"arg.y",arg.y print root.winfo_pointerxy() what i get is: arg.x 102 arg.y 250 (103, 334) arg.x 3 arg.y 1 (4, 85) arg.x 1 arg.y 0 (2, 84) arg.x 0 arg.y 0 (1, 84) why arg.x , arg.y !== root.winfo_pointerxy() ------------------ 原始邮件 ------------------ 发件人: "Cameron Laird"<Cameron(a)phaseit.net>; 发送时间: 2011年9月1日(星期四) 晚上11:19 收件人: "Douglas S. Blank"<dblank(a)cs.brynmawr.edu>; 抄送: "tkinter-discuss"<tkinter-discuss(a)python.org>; 主题: Re: [Tkinter-discuss] get root.winfo_pointerxy() On Thu, Sep 01, 2011 at 10:37:31AM -0400, Douglas S. Blank wrote: . . . > On 09/01/2011 10:21 AM, wrote: > >def myprint(): > > print root.winfo_pointerxy() > > > >canvas.bind("<Button-1>",myprint) > > When you bind a function to the canvas, it is expecting a function that > takes an argument (which is probably the object to which the binding is > bound). > > So, you could just allow myprint to take an argument, and ignore it: > > def myprint(arg): > print root.winfo_pointerxy() . . . I entirely agree with the counsel Dr. Blank has provided. While I expect the original questioner has all he needs to move forward, I'll provide a bit more detail for the benefit of other readers. Let's look at "arg", "which is probably the object to which the binding is bound". It's not; it's the detected *event* (from which that object can be calculated, though) <URL: http://www.pythonware.com/library/tkinter/introduction/events-and-bindings.… >. That's not all. One could temporarily update myprint's definition to be something like def myprint(arg): print "arg is '%s'." % arg print dir(arg) print root.winfo_pointerxy() to have Python's introspection report more information about the argument. And *that* isn't all, either. If one were somehow stranded-on-a-desert-island and unsure how many (not- necessarily-named) arguments were arriving, one could experiment with def myprint(*kw): print kw ...

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get root.winfo_pointerxy()
by 守株待兔 Sept. 1, 2011

Sept. 1, 2011

[code] from Tkinter import * root = Tk() root.title('Simple Plot - Version 1') canvas = Canvas(root, width=450, height=300, bg = 'white') canvas.pack() Button(root, text='Quit', command=root.quit).pack() canvas.create_line(100,250,400,250, width=2) canvas.create_line(100,250,100,50, width=2) for i in range(11): x = 100 + (i * 30) canvas.create_line(x,250,x,245, width=2) #canvas.create_text(x,320, text='%d'% (10*i), anchor=N) for i in range(6): y = 250 - (i * 40) canvas.create_line(100,y,105,y, width=2) canvas.create_text(96,y, text='%5.1f'% (50.*i), anchor=E) for x,y in [(12, 56), (20, 94), (33, 98), (45, 120), (61, 180), (75, 160), (98, 223)]: x = 100 + 3*x y = 250 - (4*y)/5 canvas.create_oval(x-6,y-6,x+6,y+6, width=1, outline='black', fill='SkyBlue2') def myprint(): print root.winfo_pointerxy() canvas.bind("<Button-1>",myprint) root.mainloop() [/code] when i click my left mouse,there is a output: File "/usr/lib/python2.7/lib-tk/Tkinter.py", line 1413, in __call__ return self.func(*args) TypeError: myprint() takes no arguments (1 given) what's wrong?

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one pixel=how many mm?
by 守株待兔 Sept. 1, 2011

Sept. 1, 2011

in tkinter ,you can express width in cm ,mm,inch,,pixel i want to know: one pixel=how many mm?

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