On 11/27/05, Olivier Laurent olilau.list.1@gmail.com wrote:
Here is how I tried:
# [...]
PATH = '/var/www/'
pt_resource = static.File(PATH) pt_resource.processors = { '.pt' : PTResource } pt_resource.indexNames = [ 'index' + '.pt' ]
rst_resource = static.File( PATH ) rst_resource.processors = { '.rst' : RSTResource } rst_resource.indexNames = [ 'index' + '.rst' ]
#root = Resource() # I tried this too root = static.File(PATH)
root.putChild(PATH, pt_resource) root.putChild(PATH, rst_resource)
The point of the resource name is to differenciate it from its siblings. If you give the same name to both of course it does not work. Moreover, I don't think '/var/www/' a valid resource name. Either use different "logical" names for each File, or use different processors for a single File.
I think you want something like:
my_resource = static.File(PATH) my_resource.processors = { '.pt' : PTResource, '.rst' : RSTResource} my_resource.indexNames = [ 'index.pt', 'index.rst' ] root.putChild('foo', my_resource)
Eric.