Assync method on render_POST(self,request)
My code looks like this: ... # class Site(Resource) def render_POST(self,request) otherclass.doAssync(request.args) print '1' return "done" #that returns the HTTP response, always the same. ... def doAssync(self,msg): d = defer.Deferred() reactor.callLater(0,self.doStuff,d,msg) d.addCallback(self.sucess) def doStuff(self,d,msg): # do some stuff time.sleep(2) #just for example d.callback('ok') def sucess(msg): print msg The output: 1 ok So far, so good, but, the HTTP response (return 'done'), only happens after the delay (time.sleep(2)). I can tell this, because the browser keeps 'loading' for 2 seconds. What am I doing wrong? Found some answer saying that wsgi twisted does not suport assync, and maybe Tornado could do this. ... is that true? Thanks anyway! Att, -- *João Ricardo Mattos e Silva* Graduando em Ciência da Computação na Universidade Federal de Santa Catarina *Cel: *+55 (48) 96190063 | *Skype:* jricardomsilva | * Msn: * joaoricardo@globalite.com.br
On 12:26 pm, joaoricardo000@gmail.com wrote:
[snip]
def doStuff(self,d,msg): # do some stuff time.sleep(2) #just for example d.callback('ok')
[snip] So far, so good, but, the HTTP response (return 'done'), only happens after the delay (time.sleep(2)). I can tell this, because the browser keeps 'loading' for 2 seconds.
What am I doing wrong?
Answered on Stack Overflow: http://stackoverflow.com/questions/9310350/twisted-non-blocking-method- how-to
Found some answer saying that wsgi twisted does not suport assync, and maybe Tornado could do this. ... is that true?
By definition, WSGI applications are not asynchronous. However, your code is not a WSGI application, so the nature of WSGI applications is irrelevant. Tornado doesn't change these facts. WSGI for Tornado is the same as WSGI for anything else. Jean-Paul
Thanks for the answer, really helped, but I'm stuck again in other case. http://stackoverflow.com/questions/9335509/using-wsgi-on-twisted I'm using mod_wsgi now, and I'm really lost about how to use twisted methods. Thanks again! 2012/2/16 <exarkun@twistedmatrix.com>
On 12:26 pm, joaoricardo000@gmail.com wrote:
[snip]
def doStuff(self,d,msg): # do some stuff time.sleep(2) #just for example d.callback('ok')
[snip] So far, so good, but, the HTTP response (return 'done'), only happens after the delay (time.sleep(2)). I can tell this, because the browser keeps 'loading' for 2 seconds.
What am I doing wrong?
Answered on Stack Overflow:
http://stackoverflow.com/questions/9310350/twisted-non-blocking-method- how-to
Found some answer saying that wsgi twisted does not suport assync, and maybe Tornado could do this. ... is that true?
By definition, WSGI applications are not asynchronous. However, your code is not a WSGI application, so the nature of WSGI applications is irrelevant.
Tornado doesn't change these facts. WSGI for Tornado is the same as WSGI for anything else.
Jean-Paul
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-- *João Ricardo Mattos e Silva* Graduando em Ciência da Computação na Universidade Federal de Santa Catarina *Cel: *+55 (48) 96190063 | *Skype:* jricardomsilva | * Msn: * joaoricardo@globalite.com.br
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exarkun＠twistedmatrix.com -
João Ricardo Mattos e Silva