[Twisted-Python] Get IP of connecting client in XMLRPC server

Hello,

On 18 May 2004, the following message was posted to this mailinglist:

Jp Calderone exarkun at divmod.com wrote:

Daniel Newton wrote:

I have a simple XML-PRC server similar to the example below:

from twisted.web import xmlrpc, server

class Example(xmlrpc.XMLRPC): """An example object to be published."""

def xmlrpc_add(self, a, b):
    """Return sum of arguments."""
    return a + b

def xmlrpc_whatIsMyAddress(self): return self.transport.getPeer().host

if __name__ == '__main__': from twisted.internet import reactor r = Example() reactor.listenTCP(7080, server.Site(r)) reactor.run()

I want to be able to get the address of the client that calls the

xmlrpc

method can anyone help me with this?

This solution didn't work because 'transport' isn't a property of the Example class.

I'm currently in the process of changing from a customized SimpleXMLRPCServer to a twisted XMLRPC server solution and I need to insert the client IP into the attributes passed to the called xmlrpc method. Anyone who knows the answer and is willing to share the info?

Regards, Remy