[Twisted-Python] Get IP of connecting client in XMLRPC server

11 Jun 2004

      Hello,

On 18 May 2004, the following message was posted to this mailinglist:

Jp Calderone exarkun at divmod.com wrote:
...
Daniel Newton wrote:
I have a simple XML-PRC server similar to the example below:
from twisted.web import xmlrpc, server
class Example(xmlrpc.XMLRPC):
    """An example object to be published."""
def xmlrpc_add(self, a, b):
        """Return sum of arguments."""
        return a + b
def xmlrpc_whatIsMyAddress(self):
           return self.transport.getPeer().host
...
if __name__ == '__main__':
    from twisted.internet import reactor
    r = Example()
    reactor.listenTCP(7080, server.Site(r))
    reactor.run()
I want to be able to get the address of the client that calls the
xmlrpc
...
method can anyone help me with this?
This solution didn't work because 'transport' isn't a property of the 
Example class.

I'm currently in the process of changing from a customized 
SimpleXMLRPCServer to a twisted XMLRPC server solution and I need to 
insert the client IP into the attributes passed to the called xmlrpc 
method. Anyone who knows the answer and is willing to share the info?

Regards,
Remy

[Twisted-Python] Get IP of connecting client in XMLRPC server

Remy C. Cool