Re: [Twisted-Python] Giving inlineCallbacks-wrapped functions access to the deferred their wrapper will return

On 11 Apr, 10:55 pm, terry@jon.es wrote:

I can get around this in ways that are less elegant:

@defer.inlineCallbacks def func(): # do some stuff d = defer.Deferred() callSomethingElse(d) d.callback(result) newResult = yield d defer.returnValue(newResult)

When I write functions that take a Deferred I typically have them return a Deferred as well, to avoid this, and other syntactic nuisances. Would you consider the following more elegant? @inlineCallbacks def func(): # do some stuff returnValue(yield callSomethingElse(succeed(result)))