<!--upload page--> <form method="POST" enctype="multipart/form-data" action="test.rpy"> <input type="file" name="filename"> <input type="submit"> </form> #rpy script from twisted.web.resource import Resource class test(Resource): def render_POST(self,request): f = open("/root/basic_daemon/htdocs/test/test.txt","wb") #absolute path,the path must use chmod modify authorization f.write(request.args.get('filename')[0]) f.close() return "<html><body>" + 'success' + "</body></html>" resource = test() ----by Leon---- ----- Original Message ----- From: Iap, Singuan To: leon_lee@thecus.com Sent: Monday, November 29, 2004 4:56 PM Subject: FW: [Twisted-Python] How to use .rpy do upload ? If you got answer. Why not answer yourself onto the post? singuan ------------------------------------------------------------------------------ From: twisted-python-bounces@twistedmatrix.com [mailto:twisted-python-bounces@twistedmatrix.com] On Behalf Of Leon Sent: Monday, November 29, 2004 11:43 AM To: twisted-python@twistedmatrix.com Subject: [Twisted-Python] How to use .rpy do upload ? I am a beginner,how can use .rpy do upload ???