I believe your problem is this line:

sys.exit(app.exec_())

Two issues: - It looks like app.exec_() blocks (e.g. http://stackoverflow.com/questions/22289423/how-to-avoid-qt-app-exec-blockin... ) - When it unblocks, the program sys.exit() terminates ( https://docs.python.org/2/library/sys.html#sys.exit) Thus, your app never reaches any of the twisted code. If you're not familiar with debugging tools that let you walk through the code, adding a print line between each line of actual code would have made it obvious that you never got past this line. Clayton Daley On Fri, Jun 17, 2016 at 11:26 AM, steven meier wrote:

hi,

why does the code below print "testing..." but not "123" 5 seconds after the application started?

import sys from PyQt5 import QtWidgets from untitled import Ui_MainWindow #from webchat import get_main_page

class Main(QtWidgets.QMainWindow):

def __init__(self): QtWidgets.QMainWindow.__init__(self) self.ui = Ui_MainWindow() self.ui.setupUi(self) self.setupSignals()

def button_1_Clicked(self): self.ui.textbox_2.setText(self.ui.textbox_1.text())

def setupSignals(self): #self.ui.textbox_1.textChanged.connect(self.textbox_1_Changed) self.ui.button_1.clicked.connect(self.button_1_Clicked)

if __name__ == '__main__': #app = QtWidgets.QApplication(sys.argv)

app = QtWidgets.QApplication(sys.argv) # your code to init QtCore import qt5reactor qt5reactor.install()

print "testing..."

#get_main_page() window = Main() window.show() sys.exit(app.exec_()) def printMe(argument): print argument

def lala(): reactor.callLater(5, printMe, '123')

lala() reactor.run()

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