Hi All, I'm having a little trouble with Units in YT3.0. I want to calculate the rates for some collisional dissociations as used in Enzo. The rates are fits so the dimensions are not going to be as required and YT doesn't like that! An example script showing the problem is shown below: ##################################################### import yt from yt.utilities.physical_constants import kboltz import numpy as np def _k7(field, data): #H + e > HM + gamma Tergs = data["Temperature"]*kboltz TeV = Tergs.convert_to_units('eV') krate = 6.77e15*np.power(TeV, 0.8779) return krate #cm^3 s^1 yt.add_field(("gas", "k7rate"), units="cm**3/s", function=_k7) Filename = "....../RD0000/RD0000" ds = yt.load(Filename) sp = ds.sphere('max', (100, 'kpc')) print sp["k7rate"] ####################################################### The script fails with the error: yt.utilities.exceptions.YTUnitConversionError: Unit dimensionalities do not match. Tried to convert between eV**(8779/10000) (dim (length)**(8779/5000)*(mass)**(8779/10000)/(time)**(8779/5000)) and cm**3/s (dim (length)**3/(time)). which makes sense because the _k7() function is just a fit based on temperature. Is there a way to "set" the units of k7 to be cm^3 s^1? Cheers, John
Hi John, I think you should be able to wipe out the units being used in the function and add your own by doing: return data.ds.arr(krate.d, "cm**3/s") krate.d gives you just the data array without units. Britton On Fri, Sep 26, 2014 at 7:05 AM, John Regan <johnanthonyregan@gmail.com> wrote:
Hi All,
I'm having a little trouble with Units in YT3.0.
I want to calculate the rates for some collisional dissociations as used in Enzo. The rates are fits so the dimensions are not going to be as required and YT doesn't like that!
An example script showing the problem is shown below:
##################################################### import yt from yt.utilities.physical_constants import kboltz import numpy as np
def _k7(field, data): #H + e > HM + gamma Tergs = data["Temperature"]*kboltz TeV = Tergs.convert_to_units('eV') krate = 6.77e15*np.power(TeV, 0.8779) return krate #cm^3 s^1
yt.add_field(("gas", "k7rate"), units="cm**3/s", function=_k7)
Filename = "....../RD0000/RD0000"
ds = yt.load(Filename) sp = ds.sphere('max', (100, 'kpc')) print sp["k7rate"] #######################################################
The script fails with the error: yt.utilities.exceptions.YTUnitConversionError: Unit dimensionalities do not match. Tried to convert between eV**(8779/10000) (dim (length)**(8779/5000)*(mass)**(8779/10000)/(time)**(8779/5000)) and cm**3/s (dim (length)**3/(time)).
which makes sense because the _k7() function is just a fit based on temperature. Is there a way to "set" the units of k7 to be cm^3 s^1?
Cheers, John
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Yip that works! Thanks Britton! On Fri, Sep 26, 2014 at 2:35 PM, Britton Smith <brittonsmith@gmail.com> wrote:
Hi John,
I think you should be able to wipe out the units being used in the function and add your own by doing:
return data.ds.arr(krate.d, "cm**3/s")
krate.d gives you just the data array without units.
Britton
On Fri, Sep 26, 2014 at 7:05 AM, John Regan <johnanthonyregan@gmail.com> wrote:
Hi All,
I'm having a little trouble with Units in YT3.0.
I want to calculate the rates for some collisional dissociations as used in Enzo. The rates are fits so the dimensions are not going to be as required and YT doesn't like that!
An example script showing the problem is shown below:
##################################################### import yt from yt.utilities.physical_constants import kboltz import numpy as np
def _k7(field, data): #H + e > HM + gamma Tergs = data["Temperature"]*kboltz TeV = Tergs.convert_to_units('eV') krate = 6.77e15*np.power(TeV, 0.8779) return krate #cm^3 s^1
yt.add_field(("gas", "k7rate"), units="cm**3/s", function=_k7)
Filename = "....../RD0000/RD0000"
ds = yt.load(Filename) sp = ds.sphere('max', (100, 'kpc')) print sp["k7rate"] #######################################################
The script fails with the error: yt.utilities.exceptions.YTUnitConversionError: Unit dimensionalities do not match. Tried to convert between eV**(8779/10000) (dim (length)**(8779/5000)*(mass)**(8779/10000)/(time)**(8779/5000)) and cm**3/s (dim (length)**3/(time)).
which makes sense because the _k7() function is just a fit based on temperature. Is there a way to "set" the units of k7 to be cm^3 s^1?
Cheers, John
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HI Britton, I've pretty much got everything working now as it should but there one thing that is throwing me. In the above script k7 was fairly straight forward but suppose I want to calculate the rates for something like: ###################################################### import yt from yt.utilities.physical_constants import kboltz import numpy as np def _k17(field, data): T = data["Temperature"] print "T.shape = ", T.shape k17rate = np.zeros(len(T)) i = 0 for t in T: if t < 1e4: k17rate[i] = 1.0e8*pow(t, 0.4) else: k17rate[i] = 4.0e4*pow(t, 1.4)*exp(15100.0/t) i = i + 1 return k17rate #cm^3 s^1 yt.add_field("k17rate", units="cm**3/s", function=_k17) Filename = "RD0000/RD0000" ds = yt.load(Filename) sp = ds.sphere('max', (100, 'kpc')) print sp["k17rate"] ###################################################### This time the function is messy. There is probably a nice python way of doing the calculation without looping  maybe something similar to k17rate[T < 1e4] = 1.0e8*np.power(T, 0.4) ? Either way this fails because the array that gets passed to k17 has a shape of (16, 16, 16) and so everything falls apart. The _k17 function actually gets called 5 times in total  firstly with the array of shape (16, 16, 16) and then with flat arrays but it fails on the first nonflat array anyway. Just wondering if you know what's going on here (why the function gets called 5 times and why the first array in a 3D array). Any solutions would of course also be appreciated! Cheers, John On Fri, Sep 26, 2014 at 2:41 PM, John Regan <johnanthonyregan@gmail.com> wrote:
Yip that works! Thanks Britton!
On Fri, Sep 26, 2014 at 2:35 PM, Britton Smith <brittonsmith@gmail.com> wrote:
Hi John,
I think you should be able to wipe out the units being used in the function and add your own by doing:
return data.ds.arr(krate.d, "cm**3/s")
krate.d gives you just the data array without units.
Britton
On Fri, Sep 26, 2014 at 7:05 AM, John Regan <johnanthonyregan@gmail.com> wrote:
Hi All,
I'm having a little trouble with Units in YT3.0.
I want to calculate the rates for some collisional dissociations as used in Enzo. The rates are fits so the dimensions are not going to be as required and YT doesn't like that!
An example script showing the problem is shown below:
##################################################### import yt from yt.utilities.physical_constants import kboltz import numpy as np
def _k7(field, data): #H + e > HM + gamma Tergs = data["Temperature"]*kboltz TeV = Tergs.convert_to_units('eV') krate = 6.77e15*np.power(TeV, 0.8779) return krate #cm^3 s^1
yt.add_field(("gas", "k7rate"), units="cm**3/s", function=_k7)
Filename = "....../RD0000/RD0000"
ds = yt.load(Filename) sp = ds.sphere('max', (100, 'kpc')) print sp["k7rate"] #######################################################
The script fails with the error: yt.utilities.exceptions.YTUnitConversionError: Unit dimensionalities do not match. Tried to convert between eV**(8779/10000) (dim (length)**(8779/5000)*(mass)**(8779/10000)/(time)**(8779/5000)) and cm**3/s (dim (length)**3/(time)).
which makes sense because the _k7() function is just a fit based on temperature. Is there a way to "set" the units of k7 to be cm^3 s^1?
Cheers, John
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On 09/26/2014 09:38 AM, John Regan wrote:
HI Britton,
I've pretty much got everything working now as it should but there one thing that is throwing me. In the above script k7 was fairly straight forward but suppose I want to calculate the rates for something like:
###################################################### import yt from yt.utilities.physical_constants import kboltz import numpy as np
def _k17(field, data): T = data["Temperature"] print "T.shape = ", T.shape k17rate = np.zeros(len(T)) You'd probably want something like:
k17rate = np.zeros_like(T) this will solve shape issues
i = 0 for t in T: if t < 1e4: k17rate[i] = 1.0e8*pow(t, 0.4) else: k17rate[i] = 4.0e4*pow(t, 1.4)*exp(15100.0/t) i = i + 1 return k17rate #cm^3 s^1
yt.add_field("k17rate", units="cm**3/s", function=_k17) Filename = "RD0000/RD0000"
ds = yt.load(Filename) sp = ds.sphere('max', (100, 'kpc')) print sp["k17rate"] ######################################################
This time the function is messy. There is probably a nice python way of doing the calculation without looping  maybe something similar to k17rate[T < 1e4] = 1.0e8*np.power(T, 0.4) ?
That's ^^ exactly how you want to do that. You'll need same index in power, i.e. T[T < 1e4]. Cheers, Kacper
Either way this fails because the array that gets passed to k17 has a shape of (16, 16, 16) and so everything falls apart. The _k17 function actually gets called 5 times in total  firstly with the array of shape (16, 16, 16) and then with flat arrays but it fails on the first nonflat array anyway.
Just wondering if you know what's going on here (why the function gets called 5 times and why the first array in a 3D array). Any solutions would of course also be appreciated!
Cheers, John
On Fri, Sep 26, 2014 at 2:41 PM, John Regan <johnanthonyregan@gmail.com> wrote:
Yip that works! Thanks Britton!
On Fri, Sep 26, 2014 at 2:35 PM, Britton Smith <brittonsmith@gmail.com> wrote:
Hi John,
I think you should be able to wipe out the units being used in the function and add your own by doing:
return data.ds.arr(krate.d, "cm**3/s")
krate.d gives you just the data array without units.
Britton
On Fri, Sep 26, 2014 at 7:05 AM, John Regan <johnanthonyregan@gmail.com> wrote:
Hi All,
I'm having a little trouble with Units in YT3.0.
I want to calculate the rates for some collisional dissociations as used in Enzo. The rates are fits so the dimensions are not going to be as required and YT doesn't like that!
An example script showing the problem is shown below:
##################################################### import yt from yt.utilities.physical_constants import kboltz import numpy as np
def _k7(field, data): #H + e > HM + gamma Tergs = data["Temperature"]*kboltz TeV = Tergs.convert_to_units('eV') krate = 6.77e15*np.power(TeV, 0.8779) return krate #cm^3 s^1
yt.add_field(("gas", "k7rate"), units="cm**3/s", function=_k7)
Filename = "....../RD0000/RD0000"
ds = yt.load(Filename) sp = ds.sphere('max', (100, 'kpc')) print sp["k7rate"] #######################################################
The script fails with the error: yt.utilities.exceptions.YTUnitConversionError: Unit dimensionalities do not match. Tried to convert between eV**(8779/10000) (dim (length)**(8779/5000)*(mass)**(8779/10000)/(time)**(8779/5000)) and cm**3/s (dim (length)**3/(time)).
which makes sense because the _k7() function is just a fit based on temperature. Is there a way to "set" the units of k7 to be cm^3 s^1?
Cheers, John
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you can index numpy arrays with conditions, e.g. a = arange(10) a[a < 5] = 0 print a [0 0 0 0 0 5 6 7 8 9] So you can replace the if with some indexing like this On Fri, Sep 26, 2014 at 10:38 AM, John Regan <johnanthonyregan@gmail.com> wrote:
HI Britton,
I've pretty much got everything working now as it should but there one thing that is throwing me. In the above script k7 was fairly straight forward but suppose I want to calculate the rates for something like:
###################################################### import yt from yt.utilities.physical_constants import kboltz import numpy as np
def _k17(field, data): T = data["Temperature"] print "T.shape = ", T.shape k17rate = np.zeros(len(T)) i = 0 for t in T: if t < 1e4: k17rate[i] = 1.0e8*pow(t, 0.4) else: k17rate[i] = 4.0e4*pow(t, 1.4)*exp(15100.0/t) i = i + 1 return k17rate #cm^3 s^1
yt.add_field("k17rate", units="cm**3/s", function=_k17) Filename = "RD0000/RD0000"
ds = yt.load(Filename) sp = ds.sphere('max', (100, 'kpc')) print sp["k17rate"] ######################################################
This time the function is messy. There is probably a nice python way of doing the calculation without looping  maybe something similar to k17rate[T < 1e4] = 1.0e8*np.power(T, 0.4) ?
Either way this fails because the array that gets passed to k17 has a shape of (16, 16, 16) and so everything falls apart. The _k17 function actually gets called 5 times in total  firstly with the array of shape (16, 16, 16) and then with flat arrays but it fails on the first nonflat array anyway.
Just wondering if you know what's going on here (why the function gets called 5 times and why the first array in a 3D array). Any solutions would of course also be appreciated!
Cheers, John
On Fri, Sep 26, 2014 at 2:41 PM, John Regan <johnanthonyregan@gmail.com> wrote:
Yip that works! Thanks Britton!
On Fri, Sep 26, 2014 at 2:35 PM, Britton Smith <brittonsmith@gmail.com> wrote:
Hi John,
I think you should be able to wipe out the units being used in the function and add your own by doing:
return data.ds.arr(krate.d, "cm**3/s")
krate.d gives you just the data array without units.
Britton
On Fri, Sep 26, 2014 at 7:05 AM, John Regan <johnanthonyregan@gmail.com> wrote:
Hi All,
I'm having a little trouble with Units in YT3.0.
I want to calculate the rates for some collisional dissociations as used in Enzo. The rates are fits so the dimensions are not going to be as required and YT doesn't like that!
An example script showing the problem is shown below:
##################################################### import yt from yt.utilities.physical_constants import kboltz import numpy as np
def _k7(field, data): #H + e > HM + gamma Tergs = data["Temperature"]*kboltz TeV = Tergs.convert_to_units('eV') krate = 6.77e15*np.power(TeV, 0.8779) return krate #cm^3 s^1
yt.add_field(("gas", "k7rate"), units="cm**3/s", function=_k7)
Filename = "....../RD0000/RD0000"
ds = yt.load(Filename) sp = ds.sphere('max', (100, 'kpc')) print sp["k7rate"] #######################################################
The script fails with the error: yt.utilities.exceptions.YTUnitConversionError: Unit dimensionalities do not match. Tried to convert between eV**(8779/10000) (dim (length)**(8779/5000)*(mass)**(8779/10000)/(time)**(8779/5000)) and cm**3/s (dim (length)**3/(time)).
which makes sense because the _k7() function is just a fit based on temperature. Is there a way to "set" the units of k7 to be cm^3 s^1?
Cheers, John
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 Michael Zingale Associate Professor Dept. of Physics & Astronomy • Stony Brook University • Stony Brook, NY 117943800 *phone*: 6316328225 *email*: Michael.Zingale@stonybrook.edu *web*: http://www.astro.sunysb.edu/mzingale
Hi John, Following up on Kacper's comment, which is what I was going to suggest :): The 'data' passed to a field is actually a chunk of data, and the chunking method depends on how it was implemented in the frontend. That said, the derived field should be somewhat agnostic to 'data's size/shape. In your case, you get around this by saying you want k17rate to be np.zeros_like(T), which means to have the same shape as T. On Fri, Sep 26, 2014 at 8:38 AM, John Regan <johnanthonyregan@gmail.com> wrote:
HI Britton,
I've pretty much got everything working now as it should but there one thing that is throwing me. In the above script k7 was fairly straight forward but suppose I want to calculate the rates for something like:
###################################################### import yt from yt.utilities.physical_constants import kboltz import numpy as np
def _k17(field, data): T = data["Temperature"] print "T.shape = ", T.shape k17rate = np.zeros(len(T)) i = 0 for t in T: if t < 1e4: k17rate[i] = 1.0e8*pow(t, 0.4) else: k17rate[i] = 4.0e4*pow(t, 1.4)*exp(15100.0/t) i = i + 1 return k17rate #cm^3 s^1
yt.add_field("k17rate", units="cm**3/s", function=_k17) Filename = "RD0000/RD0000"
ds = yt.load(Filename) sp = ds.sphere('max', (100, 'kpc')) print sp["k17rate"] ######################################################
This time the function is messy. There is probably a nice python way of doing the calculation without looping  maybe something similar to k17rate[T < 1e4] = 1.0e8*np.power(T, 0.4) ?
Either way this fails because the array that gets passed to k17 has a shape of (16, 16, 16) and so everything falls apart. The _k17 function actually gets called 5 times in total  firstly with the array of shape (16, 16, 16) and then with flat arrays but it fails on the first nonflat array anyway.
Just wondering if you know what's going on here (why the function gets called 5 times and why the first array in a 3D array). Any solutions would of course also be appreciated!
Cheers, John
On Fri, Sep 26, 2014 at 2:41 PM, John Regan <johnanthonyregan@gmail.com> wrote:
Yip that works! Thanks Britton!
On Fri, Sep 26, 2014 at 2:35 PM, Britton Smith <brittonsmith@gmail.com> wrote:
Hi John,
I think you should be able to wipe out the units being used in the function and add your own by doing:
return data.ds.arr(krate.d, "cm**3/s")
krate.d gives you just the data array without units.
Britton
On Fri, Sep 26, 2014 at 7:05 AM, John Regan <johnanthonyregan@gmail.com> wrote:
Hi All,
I'm having a little trouble with Units in YT3.0.
I want to calculate the rates for some collisional dissociations as used in Enzo. The rates are fits so the dimensions are not going to be as required and YT doesn't like that!
An example script showing the problem is shown below:
##################################################### import yt from yt.utilities.physical_constants import kboltz import numpy as np
def _k7(field, data): #H + e > HM + gamma Tergs = data["Temperature"]*kboltz TeV = Tergs.convert_to_units('eV') krate = 6.77e15*np.power(TeV, 0.8779) return krate #cm^3 s^1
yt.add_field(("gas", "k7rate"), units="cm**3/s", function=_k7)
Filename = "....../RD0000/RD0000"
ds = yt.load(Filename) sp = ds.sphere('max', (100, 'kpc')) print sp["k7rate"] #######################################################
The script fails with the error: yt.utilities.exceptions.YTUnitConversionError: Unit dimensionalities do not match. Tried to convert between eV**(8779/10000) (dim (length)**(8779/5000)*(mass)**(8779/10000)/(time)**(8779/5000)) and cm**3/s (dim (length)**3/(time)).
which makes sense because the _k7() function is just a fit based on temperature. Is there a way to "set" the units of k7 to be cm^3 s^1?
Cheers, John
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Kacper/Michael/Chris, Thanks a million lads  that makes perfect sense! I hadn't realised the zeros_like function existed  nice one. And thanks Kacper for debugging the indexing statement that works a charm! Cheers lads. John On Fri, Sep 26, 2014 at 5:53 PM, Chris Malone <chris.m.malone@gmail.com> wrote:
Hi John,
Following up on Kacper's comment, which is what I was going to suggest :):
The 'data' passed to a field is actually a chunk of data, and the chunking method depends on how it was implemented in the frontend. That said, the derived field should be somewhat agnostic to 'data's size/shape. In your case, you get around this by saying you want k17rate to be np.zeros_like(T), which means to have the same shape as T.
On Fri, Sep 26, 2014 at 8:38 AM, John Regan <johnanthonyregan@gmail.com> wrote:
HI Britton,
I've pretty much got everything working now as it should but there one thing that is throwing me. In the above script k7 was fairly straight forward but suppose I want to calculate the rates for something like:
###################################################### import yt from yt.utilities.physical_constants import kboltz import numpy as np
def _k17(field, data): T = data["Temperature"] print "T.shape = ", T.shape k17rate = np.zeros(len(T)) i = 0 for t in T: if t < 1e4: k17rate[i] = 1.0e8*pow(t, 0.4) else: k17rate[i] = 4.0e4*pow(t, 1.4)*exp(15100.0/t) i = i + 1 return k17rate #cm^3 s^1
yt.add_field("k17rate", units="cm**3/s", function=_k17) Filename = "RD0000/RD0000"
ds = yt.load(Filename) sp = ds.sphere('max', (100, 'kpc')) print sp["k17rate"] ######################################################
This time the function is messy. There is probably a nice python way of doing the calculation without looping  maybe something similar to k17rate[T < 1e4] = 1.0e8*np.power(T, 0.4) ?
Either way this fails because the array that gets passed to k17 has a shape of (16, 16, 16) and so everything falls apart. The _k17 function actually gets called 5 times in total  firstly with the array of shape (16, 16, 16) and then with flat arrays but it fails on the first nonflat array anyway.
Just wondering if you know what's going on here (why the function gets called 5 times and why the first array in a 3D array). Any solutions would of course also be appreciated!
Cheers, John
On Fri, Sep 26, 2014 at 2:41 PM, John Regan <johnanthonyregan@gmail.com> wrote:
Yip that works! Thanks Britton!
On Fri, Sep 26, 2014 at 2:35 PM, Britton Smith <brittonsmith@gmail.com> wrote:
Hi John,
I think you should be able to wipe out the units being used in the function and add your own by doing:
return data.ds.arr(krate.d, "cm**3/s")
krate.d gives you just the data array without units.
Britton
On Fri, Sep 26, 2014 at 7:05 AM, John Regan <johnanthonyregan@gmail.com
wrote:
Hi All,
I'm having a little trouble with Units in YT3.0.
I want to calculate the rates for some collisional dissociations as used in Enzo. The rates are fits so the dimensions are not going to be as required and YT doesn't like that!
An example script showing the problem is shown below:
##################################################### import yt from yt.utilities.physical_constants import kboltz import numpy as np
def _k7(field, data): #H + e > HM + gamma Tergs = data["Temperature"]*kboltz TeV = Tergs.convert_to_units('eV') krate = 6.77e15*np.power(TeV, 0.8779) return krate #cm^3 s^1
yt.add_field(("gas", "k7rate"), units="cm**3/s", function=_k7)
Filename = "....../RD0000/RD0000"
ds = yt.load(Filename) sp = ds.sphere('max', (100, 'kpc')) print sp["k7rate"] #######################################################
The script fails with the error: yt.utilities.exceptions.YTUnitConversionError: Unit dimensionalities do not match. Tried to convert between eV**(8779/10000) (dim (length)**(8779/5000)*(mass)**(8779/10000)/(time)**(8779/5000)) and cm**3/s (dim (length)**3/(time)).
which makes sense because the _k7() function is just a fit based on temperature. Is there a way to "set" the units of k7 to be cm^3 s^1?
Cheers, John
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participants (5)

Britton Smith

Chris Malone

John Regan

Kacper Kowalik

Michael Zingale