[BangPypers] which one is the best pythonic way .
anandology at gmail.com
Tue Feb 9 06:07:55 CET 2010
On Tue, Feb 9, 2010 at 10:22 AM, Srinivas Reddy Thatiparthy
<srinivas_thatiparthy at akebonosoft.com> wrote:
> I have written four solutions to a problem(self explanatory) ,out of
> them ,which one is the pythonic way of doing and
> is there any other ways of solving it?
> 1.sum([i for i in range(1000) if i%3==0 or i%5==0])
> 2.gen=(i for i in range(1000))
> sum([i for i in gen if i%3==0 or i%5==0])
> 3.sum(filter(lambda a:a%3==0 or a%5==0,range(1000)))
> 4.def generator(m):
> while count<m:
> if count%3==0 or count%5==0:
> yield count
> sum([i for i in generator(1000)])
You can even remove the square brackets.
sum(i for i in range(1000) if i%3==0 or i%5==0)
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