[BangPypers] list problem

[steve]

Hi,

On 07/22/2010 05:02 PM, Anand Balachandran Pillai wrote:
> On Thu, Jul 22, 2010 at 3:21 PM, Vikram<kpguy at rediffmail.com>  wrote:
>
>>  Suppose you have the following list:
>>
>>  >>>  x =[['cat',10],['cat',20],['cat',30],['dog',5],['dog',1],['dog',3]]
>>
>>  My problem is that i wish to obtain the following two dictionaries:
>>  xdictstart = {'cat':10, 'dog':1}
>>  xdictend = {'cat':30, 'dog':5}
>
>
>>  Any nice way to do the above? Thanks.
>>
>>
> Yes. Try this.
>
>>>>  x =[['cat',10],['cat',20],['cat',30],['dog',5],['dog',1],['dog',3]]
>>>>  x.sort()
>>>>  xdictstart = dict(reversed(x))
>>>>  xdictend = dict(x)
>>>>  xdictstart,xdictend
> ({'dog': 1, 'cat': 10}, {'dog': 5, 'cat': 30})

Are you sure that'll work ? Is creating a dict from a sequence guaranteed to be 
executed serially withing the sequence ?

cheers,
- steve
-- 
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