[BangPypers] plist files
vinayshastry at gmail.com
Mon Mar 14 20:51:05 CET 2011
On 14 March 2011 17:21, Python User <python.user.01 at gmail.com> wrote:
> Hi All,
> I have a plist file, test.plist, All I want is read the scriptNO tag value
> 12345 and replace it with 67899. Can any one please help me out for
> this. The file content is
> <?xml version="1.0" encoding="UTF-8"?>
> <!DOCTYPE plist PUBLIC "-//test//EN" "
> <plist version="1.0">
> <string>Get Test Script</string>
> <string>Test case</string>
> I was using the below code to read the plist file, but I am not able to
> search the scriptNo and replace it with other value.
> import plistlib
> file = ('/Users/me/Desktop/test.plist')
> plist = plistlib.readPlist(file)
> print plist
> Please help me out to solve this. Thanks In Advance.
The answer is in your plist format itself. Everything is enclosed in
an array - which becomes a list in py.
How about something like this:
for key in plist:
if 'opParam' in key and 'scriptNO' in key['opParam']:
key['opParam']['scriptNO'] = 67899
Also, is there a reason why file is a tuple containing filename, and
not just a string?
Vinay S Shastry
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