[BangPypers] File operations

[Shashidhar Paragonda]

Hello Noufal  I have tried your solution but i get invalid syntax for this
line *with open(............)
*I am using python 2.3.5 what could be the problem.

On Wed, Oct 19, 2011 at 3:52 PM, Noufal Ibrahim <noufal at gmail.com> wrote:

> Shashidhar Paragonda <shashidhar85 at gmail.com> writes:
>
> > Dear Python hackers,
> >
> >         I have a text file and the contents are like :
> >
> >                             #(
> >                             #resultToExportToCurveDistDialog ' ->'
> >                             #off)
> >
> >         like same structure many lines exists.
> >         My requirement is I want to find line where
> > "resultToExportCurveDistDialog" and other pattern exist. After that I
> need
> > to fetch the value of it. in above example value
> >         for "resultToExportCurveDistDialog" is  "off" how to move file
> > pointer to next line and fetch value as soon as i find my required
> patterns.
> >         Thank you in advance for the help.
>
> Something like this? Untested.
>
> keywords = set(["resultToExportToCurveDistDialog",
> "resultToExportCurveDistDialog2"...])
>
> with open("file.txt", r) as f:
>        for line in f:
>            keyword = line.strip("#").split()[0].strip()
>            if keyword in keywords:
>                value = f.next()
>                print "%s : %s"%(keyword, value)
>
>
> --
> ~noufal
> http://nibrahim.net.in
>
> A verbal contract isn't worth the paper it's written on. Include me out.
> -Samuel Goldwyn
> _______________________________________________
> BangPypers mailing list
> BangPypers at python.org
> http://mail.python.org/mailman/listinfo/bangpypers
>



-- 
-----------------------------------
Regards,

Shashidhar N.Paragonda
shashidhar85 at gmail.com
+919449073835