[BangPypers] need help w.r.t itertools

[Suyash Bhatt]

thanks for the response..

what if i have another list

*e = [*'*my1name1is1','**my2name2is1','xyz','abc']*
*and in the list d, I want only the elements which are present in e..*
*
*
*in such a case,*
*d should have only 2 elements : ['**my1name1is1','**my2name2is1']*
*
*
i want the way with the least cyclomatic complexity to be able to do all
this!!


FYR :

*a=[‘my1’,’my2’]
*

**

*b=[‘name1’,’name2’]*

*c=[‘is1’]*

 I want to iter through all and form another list with the following
appended strings:

*d=['my1name1is1','my1name2is1','my2name1is1','my2name2is1']*

Can this be done in a single line using the itertools module??


Regards,

Suyash


On Fri, Sep 13, 2013 at 6:09 PM, Saager Mhatre <saager.mhatre at gmail.com>wrote:

> On Fri, Sep 13, 2013 at 5:01 PM, Dhruv Baldawa <dhruvbaldawa at gmail.com
> >wrote:
>
> > d = [''.join(x) for x in itertools.product(a, b, c)]
> >
>
> Actually, using itertools.imap would ensure that the elements aren't
> computed till necessary. So...
>
> d = itertools.imap(''.join, itertools.product(a, b, c))
>
> - d
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