[Baypiggies] What is happening here with true/false comparisons

[Brent Pedersen]

http://docs.python.org/reference/expressions.html#summary

so == and 'in' have the same precedence. so your statement is equivalent to:

  >>> ((a in alist) == b) in alist



On Mon, Jan 25, 2010 at 1:12 PM, Max Slimmer <max at theslimmers.net> wrote:
> Can anyone explain the following:
>
>>>> a = 1
>>>> b = 2
>>>> alist = [5,6]
>>>> print a in alist
> False
>
>>>> a in alist == b in alist
> False
>>>> a in alist == a in alist
> False
>>>> bool(a in alist) == bool(b in alist)      # this does what we expect
> True
>>>> c = 5
>>>> c in alist == c in alist
> False
>>>>
>
> max
>
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