[Baypiggies] rounding off problem
Stephen Cattaneo
stephen.cattaneo at gmail.com
Wed Mar 23 17:33:07 CET 2011
>>> x = 3.223344
>>> z = round(x,3)
>>> z
3.2229999999999999
>>> print z
3.223
On Wed, Mar 23, 2011 at 8:34 AM, Vikram K <kpguy1975 at gmail.com> wrote:
> how does one round off a float number in python? i have tried this using
> two ways but have been unsuccessful so far:
>
> 1. IDLE 2.6.6 ==== No Subprocess ====
> >>> x = 3.5666666
> >>> x = round(x,3)
> >>> x
> 3.5670000000000002
>
> [ The above works when i try doing x = round(x,2). I am working on a
> windows machine. The above seems to work on the linux machine of a colleague
> but he gets the same problem when he tries x = round(x,4)]
>
> 2. >>> from decimal import *
> >>> getcontext().prec = 3
> >>> x = decimal(3.456654)
>
> >>> x = Decimal('3.2213333')
> >>> x
> Decimal('3.2213333')
> >>> getcontext().prec = 5
> >>> x
> Decimal('3.2213333')
> >>> y = round(x,3)
> >>> y
> 3.2210000000000001
> >>> x = 3.223344
> >>> z = round(x,3)
> >>> z
> 3.2229999999999999
>
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--
---
Failures are finger posts on the road to achievement.
-- C.S. Lewis
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