[Baypiggies] Another Python koan: modifying a list

Damon McCormick damonmc at gmail.com
Wed Nov 16 04:52:38 CET 2011


What is the intent of the following line?

  x[i:i+1] = items

Namely, what is the purpose of blowing away item i of x every time you
insert a new list of items into x?

Is it possible that you mean something more like the following?


If so, you could just do this:

  for element in mylist:
      items = element.split(',')

Or even this:

  x = [item for element in mylist for item in element.split(,)]


On Tue, Nov 15, 2011 at 7:35 PM, Casey Callendrello <c1 at caseyc.net> wrote:

> Howdy there,
> Another python puzzle for everyone. I've been trying to come up with a
> Pythonic (i.e. no index variable) way of solving this.
> I have a list consisting of one or more independent arguments to a
> specific command-line option. Think ./foo.py -a 1 -a 15 -a 1203. Argparse
> handles this fine. However, a few of my users prefer to specify arguments
> separated by commas instead. This is a fairly reasonable on their part, as
> about half of the tools we use like it one way, and half prefer the other.
> I don't mind supporting both, and the input data can never have a comma
> otherwise.
> So, is there another way to express this code? In reality, the number of
> arguments is very small, so duplicating the array is no big deal. I'm still
> interested in a cleaner solution :-)
> i = 0
> while i < len(mylist):
>    items = mylist[i].split(',')
>    if len(items) > 1:
>        x[i:i+1] = items
>    i++
> --Casey Callendrello
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