[Baypiggies] Another Python koan: modifying a list
c1 at caseyc.net
Wed Nov 16 05:02:05 CET 2011
It's a typo.I meant mylist[i:i+1] = items. And, of course, i += 1. Long day.
On 11/15/11 7:52 PM, Damon McCormick wrote:
> What is the intent of the following line?
> x[i:i+1] = items
> Namely, what is the purpose of blowing away item i of x every time you
> insert a new list of items into x?
> Is it possible that you mean something more like the following?
> If so, you could just do this:
> for element in mylist:
> items = element.split(',')
> Or even this:
> x = [item for element in mylist for item in element.split(,)]
> On Tue, Nov 15, 2011 at 7:35 PM, Casey Callendrello <c1 at caseyc.net
> <mailto:c1 at caseyc.net>> wrote:
> Howdy there,
> Another python puzzle for everyone. I've been trying to come up
> with a Pythonic (i.e. no index variable) way of solving this.
> I have a list consisting of one or more independent arguments to a
> specific command-line option. Think ./foo.py -a 1 -a 15 -a 1203.
> Argparse handles this fine. However, a few of my users prefer to
> specify arguments separated by commas instead. This is a fairly
> reasonable on their part, as about half of the tools we use like
> it one way, and half prefer the other. I don't mind supporting
> both, and the input data can never have a comma otherwise.
> So, is there another way to express this code? In reality, the
> number of arguments is very small, so duplicating the array is no
> big deal. I'm still interested in a cleaner solution :-)
> i = 0
> while i < len(mylist):
> items = mylist[i].split(',')
> if len(items) > 1:
> x[i:i+1] = items
> --Casey Callendrello
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