[Chicago] constant length string manipulation

[Cosmin Stejerean]

You are correct, I meant to say "has turned". Although I bet it could  
get worse (or better depending on your point of view).

Cosmin Stejerean (m)


On Dec 2, 2007, at 10:07 AM, Carl Karsten <carl at personnelware.com>  
wrote:

> Cosmin Stejerean wrote:
>> In case everyone forgot, this is Python not perl: there is only one
>> way to do it (it just so happens to be my way)
>
> you way is... let me check... "stupid!"
>
>>
>> This is turning into an exercise of writing obfuscated code.
>
> turning into?  you mean we aren't their yet?  I can hardly wait till  
> the real
> obfuscation starts happening.
>
>>
>> Cosmin Stejerean (m)
>>
>>
>> On Dec 2, 2007, at 7:48 AM, Massimo Di Pierro
>> <mdipierro at cs.depaul.edu> wrote:
>>
>>> c'mon. No loops... and why limit to ' ' padding?
>>>
>>> import re
>>> f=lambda a,n,c=' ': re.compile('.{%i}'%n).findall(a+c*n)[0]
>>> f('hello world',5)
>>>
>>> Massimo
>>>
>>> On Dec 2, 2007, at 9:42 AM, Carl Karsten wrote:
>>>
>>>> def s5(s):
>>>>  if len(s)<>5:
>>>>    s=s5((s+' ')[:5])
>>>>  return s
>>>>
>>>> print s5('Hello Worlds').__repr__()
>>>> print s5('He').__repr__()
>>>>
>>>> The :5 blows the elegance.
>>>>
>>>> I thought I could +1 and -1 at the same time and have it converge
>>>> on 5, but that
>>>> didn't work.
>>>>
>>>> Carl K
>>>>
>>>>
>>>>
>>>> Jeff Hinrichs - DM&T wrote:
>>>>> Actually, this kind of problem just screams recursion
>>>>>
>>>>> def s5(s):
>>>>>     if len(s) < 5: s=s5(s+' ')
>>>>>     if len(s) > 5: s=s5(s[:-1])
>>>>>     return s
>>>>>
>>>>> print s5('Hello Worlds')
>>>>>
>>>>>
>>>>> On Dec 2, 2007 12:26 AM, Massimo Di Pierro
>>>>> <mdipierro at cs.depaul.edu> wrote:
>>>>>> f=lambda a,n: (a[:n]+' '*n)[:n] # theta(n) for every a
>>>>>> f('hello world',5)
>>>>>>
>>>>>>
>>>>>> On Dec 2, 2007, at 12:14 AM, Cosmin Stejerean wrote:
>>>>>>
>>>>>>> It's cheating. What if he wanted 10 instead of 5? Hardcoding
>>>>>>> spaces is
>>>>>>> a bad idea.
>>>>>>>
>>>>>>> Cosmin Stejerean (m)
>>>>>>>
>>>>>>>
>>>>>>> On Dec 1, 2007, at 9:29 PM, Carl Karsten  
>>>>>>> <carl at personnelware.com>
>>>>>>> wrote:
>>>>>>>
>>>>>>>> string concatenation is icky.
>>>>>>>>
>>>>>>>> you have too many 5s.
>>>>>>>>
>>>>>>>> the line is too long.
>>>>>>>>
>>>>>>>> your variables are too short.
>>>>>>>>
>>>>>>>> there are no comments.
>>>>>>>>
>>>>>>>> and it isn't OOP.
>>>>>>>>
>>>>>>>> Carl K
>>>>>>>>
>>>>>>>> Massimo Di Pierro wrote:
>>>>>>>>> what's wrong with
>>>>>>>>>
>>>>>>>>> b=(a[:5]+'     ')[:5]
>>>>>>>>>
>>>>>>>>> Massimo
>>>>>>>>>
>>>>>>>>> On Nov 30, 2007, at 9:25 AM, Lukasz Szybalski wrote:
>>>>>>>>>
>>>>>>>>>> On Nov 29, 2007 3:29 PM, Cosmin Stejerean
>>>>>>>>>> <cstejerean at gmail.com>
>>>>>>>>>> wrote:
>>>>>>>>>>> b.ljust(5)[:5]
>>>>>>>>>> a='1234567890' or a='123'
>>>>>>>>>> b=a.ljust(5)[:5]
>>>>>>>>>>
>>>>>>>>>> so I guess ljust will do.
>>>>>>>>>> Thanks.
>>>>>>>>>> Lucas
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