[Chicago] constant length string manipulation

[Carl Karsten]

You set fire to the town!
But I put the fires out.
Out?!  you made them worse!
Worse, or better?

Cosmin Stejerean wrote:
> You are correct, I meant to say "has turned". Although I bet it could  
> get worse (or better depending on your point of view).
> 
> Cosmin Stejerean (m)
> 
> 
> On Dec 2, 2007, at 10:07 AM, Carl Karsten <carl at personnelware.com>  
> wrote:
> 
>> Cosmin Stejerean wrote:
>>> In case everyone forgot, this is Python not perl: there is only one
>>> way to do it (it just so happens to be my way)
>> you way is... let me check... "stupid!"
>>
>>> This is turning into an exercise of writing obfuscated code.
>> turning into?  you mean we aren't their yet?  I can hardly wait till  
>> the real
>> obfuscation starts happening.
>>
>>> Cosmin Stejerean (m)
>>>
>>>
>>> On Dec 2, 2007, at 7:48 AM, Massimo Di Pierro
>>> <mdipierro at cs.depaul.edu> wrote:
>>>
>>>> c'mon. No loops... and why limit to ' ' padding?
>>>>
>>>> import re
>>>> f=lambda a,n,c=' ': re.compile('.{%i}'%n).findall(a+c*n)[0]
>>>> f('hello world',5)
>>>>
>>>> Massimo
>>>>
>>>> On Dec 2, 2007, at 9:42 AM, Carl Karsten wrote:
>>>>
>>>>> def s5(s):
>>>>>  if len(s)<>5:
>>>>>    s=s5((s+' ')[:5])
>>>>>  return s
>>>>>
>>>>> print s5('Hello Worlds').__repr__()
>>>>> print s5('He').__repr__()
>>>>>
>>>>> The :5 blows the elegance.
>>>>>
>>>>> I thought I could +1 and -1 at the same time and have it converge
>>>>> on 5, but that
>>>>> didn't work.
>>>>>
>>>>> Carl K
>>>>>
>>>>>
>>>>>
>>>>> Jeff Hinrichs - DM&T wrote:
>>>>>> Actually, this kind of problem just screams recursion
>>>>>>
>>>>>> def s5(s):
>>>>>>     if len(s) < 5: s=s5(s+' ')
>>>>>>     if len(s) > 5: s=s5(s[:-1])
>>>>>>     return s
>>>>>>
>>>>>> print s5('Hello Worlds')
>>>>>>
>>>>>>
>>>>>> On Dec 2, 2007 12:26 AM, Massimo Di Pierro
>>>>>> <mdipierro at cs.depaul.edu> wrote:
>>>>>>> f=lambda a,n: (a[:n]+' '*n)[:n] # theta(n) for every a
>>>>>>> f('hello world',5)
>>>>>>>
>>>>>>>
>>>>>>> On Dec 2, 2007, at 12:14 AM, Cosmin Stejerean wrote:
>>>>>>>
>>>>>>>> It's cheating. What if he wanted 10 instead of 5? Hardcoding
>>>>>>>> spaces is
>>>>>>>> a bad idea.
>>>>>>>>
>>>>>>>> Cosmin Stejerean (m)
>>>>>>>>
>>>>>>>>
>>>>>>>> On Dec 1, 2007, at 9:29 PM, Carl Karsten  
>>>>>>>> <carl at personnelware.com>
>>>>>>>> wrote:
>>>>>>>>
>>>>>>>>> string concatenation is icky.
>>>>>>>>>
>>>>>>>>> you have too many 5s.
>>>>>>>>>
>>>>>>>>> the line is too long.
>>>>>>>>>
>>>>>>>>> your variables are too short.
>>>>>>>>>
>>>>>>>>> there are no comments.
>>>>>>>>>
>>>>>>>>> and it isn't OOP.
>>>>>>>>>
>>>>>>>>> Carl K
>>>>>>>>>
>>>>>>>>> Massimo Di Pierro wrote:
>>>>>>>>>> what's wrong with
>>>>>>>>>>
>>>>>>>>>> b=(a[:5]+'     ')[:5]
>>>>>>>>>>
>>>>>>>>>> Massimo
>>>>>>>>>>
>>>>>>>>>> On Nov 30, 2007, at 9:25 AM, Lukasz Szybalski wrote:
>>>>>>>>>>
>>>>>>>>>>> On Nov 29, 2007 3:29 PM, Cosmin Stejerean
>>>>>>>>>>> <cstejerean at gmail.com>
>>>>>>>>>>> wrote:
>>>>>>>>>>>> b.ljust(5)[:5]
>>>>>>>>>>> a='1234567890' or a='123'
>>>>>>>>>>> b=a.ljust(5)[:5]
>>>>>>>>>>>
>>>>>>>>>>> so I guess ljust will do.
>>>>>>>>>>> Thanks.
>>>>>>>>>>> Lucas
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>>>>>>>>>>
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>>>>>>
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