[Chicago] A list comprehension???

[kirby urner]

On Mon, May 4, 2015 at 5:23 PM, Adam Forsyth <adam at adamforsyth.net> wrote:

> Your algorithm is equivalent to
>
> [i**2 - i for i in range(1, 11)]
>

Yep:

(1)  print([(4*n**2 + 4*n)//4 for n in range(50)])
(2)  print([sum(range(0, 2*i, 2)) for i in range(1, 50)])
(3)  print([i**2 - i for i in range(1, 50)])




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