[Chicago] Question about accessing dictionary's elements.
Joshua Herman
zitterbewegung at gmail.com
Sat Sep 19 20:58:08 CEST 2015
Yea what time on monday is good for you. can you email me off list?
zitterbewegung at gmail.com
On Sat, Sep 19, 2015 at 1:56 PM Lewit, Douglas <d-lewit at neiu.edu> wrote:
> You have any time on Monday? I really gotta get going. If I sit in front
> of this laptop any longer, I'm going to go completely crazy! I spent all
> morning working on the code for the KNN algorithm, and I'm still not really
> done with it! (But pretty close I think.... I hope! )
>
> On Sat, Sep 19, 2015 at 1:54 PM, Joshua Herman <zitterbewegung at gmail.com>
> wrote:
>
>> umm i can do skype
>>
>>
>> On Sat, Sep 19, 2015 at 1:46 PM Lewit, Douglas <d-lewit at neiu.edu> wrote:
>>
>>> Hey Joshua! I would LOVE to, but I have classes on Wednesday and
>>> Thursday evenings. So.... ???
>>>
>>> On Sat, Sep 19, 2015 at 1:30 PM, Joshua Herman <zitterbewegung at gmail.com
>>> > wrote:
>>>
>>>> Hey I'm doing machine learning too why don't you come to one of the
>>>> python meet ups in Chicago
>>>>
>>>> On Sat, Sep 19, 2015 at 12:56 PM Lewit, Douglas <d-lewit at neiu.edu>
>>>> wrote:
>>>>
>>>>> Hi William,
>>>>>
>>>>> I'm doing a KNN program (K-Nearest-Neighbors). I'm attaching what
>>>>> I've done so far. It's not complete! But I've made good progress I think.
>>>>> (The program won't work unless you also download the .txt file that the
>>>>> program uses to read in the data.)
>>>>>
>>>>> For this problem the data has to get split into two sets: a training
>>>>> set (kind of like a control group in an experiment) and the test set (the
>>>>> experimental group or its equivalent). I have to use the K smallest
>>>>> normalized distances to make a guess about which class the records in the
>>>>> Training Set belong to. (There are six classes: {1, 2, 3, 5, 6, 7}.
>>>>> There's no class #4.)
>>>>>
>>>>> This problem has given me a massive headache, but I think I'm almost
>>>>> done with it. All that's left really is to use one of the algorithms to
>>>>> make a decision about which class each Test record should be assigned to.
>>>>>
>>>>> Thanks for the feedback!
>>>>>
>>>>> Best,
>>>>>
>>>>> Douglas.
>>>>>
>>>>>
>>>>> On Sat, Sep 19, 2015 at 10:45 AM, William E. S. Clemens <
>>>>> wesclemens at gmail.com> wrote:
>>>>>
>>>>>> I would agree that Jimmy's solution is the correct one for doing
>>>>>> this. But I would avoid setting up your data structure in this manner. A
>>>>>> dict is a hash table and it is be extremely fast a looking up a value by
>>>>>> key.
>>>>>>
>>>>>> You are building an array of the keys to linearly search. This
>>>>>> operation is going to be slow and will not scale well. If you described
>>>>>> what this data is and what your trying todo with it. I maybe able to
>>>>>> suggest a better data structure for storing and accessing it.
>>>>>>
>>>>>>
>>>>>>
>>>>>>
>>>>>> --
>>>>>> William Clemens
>>>>>> Phone: 847.485.9455
>>>>>> E-mail: wesclemens at gmail.com
>>>>>>
>>>>>> On Sat, Sep 19, 2015 at 10:02 AM, Lewit, Douglas <d-lewit at neiu.edu>
>>>>>> wrote:
>>>>>>
>>>>>>> I love it! Thanks Jim.
>>>>>>>
>>>>>>> On Sat, Sep 19, 2015 at 8:09 AM, Jimmy Calahorrano via Chicago <
>>>>>>> chicago at python.org> wrote:
>>>>>>>
>>>>>>>> is more elegant but not sure if is the best option:
>>>>>>>>
>>>>>>>>
>>>>>>>> [A[key] for key in A.keys() if key[0] == 1]
>>>>>>>>
>>>>>>>>
>>>>>>>>
>>>>>>>> --------------------------------------------
>>>>>>>> On Sat, 9/19/15, Lewit, Douglas <d-lewit at neiu.edu> wrote:
>>>>>>>>
>>>>>>>> Subject: [Chicago] Question about accessing dictionary's elements.
>>>>>>>> To: "The Chicago Python Users Group" <chicago at python.org>
>>>>>>>> Date: Saturday, September 19, 2015, 7:43 AM
>>>>>>>>
>>>>>>>> Hi
>>>>>>>> guys,
>>>>>>>> I have a problem and not
>>>>>>>> sure how to address it. Let's say I have a simple
>>>>>>>> dictionary such as.
>>>>>>>> A = { (1, 2) : 10, (1, 3) :
>>>>>>>> 15, (1, 4) : 50, (2, 0) : 2, (2, 5) : 8, (2, 12) : 19
>>>>>>>> }
>>>>>>>> I would like to access any
>>>>>>>> and all tuples whose first value is 1 or let's say 2.
>>>>>>>> How would I do that?
>>>>>>>> So what I'm trying to
>>>>>>>> go for is:
>>>>>>>> A[(1, placeholder for any
>>>>>>>> int value)] thus giving me all the values that correspond to
>>>>>>>> (1, #). Not really sure how to go about this. Unless....
>>>>>>>> I suppose I could do something like
>>>>>>>> this:
>>>>>>>> for key in
>>>>>>>> A: if list(key)[0]
>>>>>>>> == 1:
>>>>>>>> print(A[key]) #### Or whatever I want to do with the
>>>>>>>> number.
>>>>>>>> Hmmm.... maybe that would
>>>>>>>> work, but is there a more "elegant" way to do
>>>>>>>> this? Is there any "pattern matching" in Python
>>>>>>>> so that I could do this:
>>>>>>>> A[(1, #placeholder for any
>>>>>>>> int )]
>>>>>>>> Hey, thanks for your
>>>>>>>> help.
>>>>>>>> By the way, has anyone seen
>>>>>>>> the book LEARNING PYTHON by Mark Lutz? Wow! Full of
>>>>>>>> great information, but the book is HUGE!!! I'll have
>>>>>>>> serious back problems if I carry that thing around in my
>>>>>>>> backpack! There's something about small, lightweight
>>>>>>>> books that I really prefer. (And then there's eBooks,
>>>>>>>> but that's a horse of a different color in my
>>>>>>>> opinion.)
>>>>>>>> Have a great weekend and
>>>>>>>> I'm looking forward to some ideas on the above
>>>>>>>> problem. Thanks in advance.
>>>>>>>> Best,
>>>>>>>> Douglas
>>>>>>>> L.
>>>>>>>>
>>>>>>>> -----Inline Attachment Follows-----
>>>>>>>>
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