[code-quality] assigning node type with function annotations?
Jarrad Hope
me at jarradhope.com
Thu May 7 18:37:03 CEST 2015
Ahh thank-you so much!
I ended up with this so I can define list, seq, dict, etc
def argument_annotation_inference(node, context=None):
_type = next(node._annotype.infer())
klass = vars(builtins)[_type.name]
return iter([CONST_CLS[klass](klass())])
On Thu, May 7, 2015 at 10:39 PM, Claudiu Popa <pcmanticore at gmail.com> wrote:
> On Thu, May 7, 2015 at 6:02 PM, Jarrad Hope <me at jarradhope.com> wrote:
>> This is how far I got with this,
>> https://gist.github.com/jarradh/02dd8f5ad07527c9fd10
>>
>> In the example go through Arguments(i imagine I'll have to apply
>> transform on functiondef later) and apply an explicit transformation,
>> and I manage to apply a Const type to all of them but I got stuck at
>> how to switch based on node._annotype.name
>> since Const instantiates with the name as a value and therefore it's a
>> string type.
>>
>> How can I switch the Const type based on node._annotype.name ?
>> Or is there a better way of going about this?
>>
>>
>
>
> You'll have to infer node._annontype.name (which can be a Class) and
> get its name. Then retrieving the name from builtins and try to go from there.
> Something along these lines:
>
> import builtins
>
> type = next(node._annotype.infer())
> const = Const(vars(builtins)[type.name]())
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