[C++-sig] python namespace

[Bjorn Pettersen]

> From: David Abrahams [mailto:dave at boost-consulting.com] 
> 
> "Achim Domma" <achim.domma at syynx.de> writes:
> 
> > Hi,
> >
> > I have the same problem like Francois. I use the following:
> >
> >   handle<> inner_module(PyModule_New("Drawable"));
> >   scope().attr("Drawable") = inner_module;
> >   scope drawable = object(inner_module);
> >
> > it works fine with VC7 but I tried it on RH8 with gcc3.2 and it
failed 
> > to compile with the same error as Francois code. Then I tried 
> > something like:
> >
> >   scope drawable = scope(object(inner_module))
> 
> Why are you messing around with that approach when I already 
> posted this correct one?
> 
>     scope drawable(object(inner_module));

Now I'm confused... If I use the following code:

  handle<> db_module(PyModule_New("db"));
  scope().attr("db") = db_module;
  scope db_scope = object(db_module);      /**/
  class_<X>("X");

X ends up in nrx.db (my main module is named nrx) and everything works
as expected. If I change the line marked /**/ to:

  scope db_scope(object(db_module));

X ends up in nrx and there's an empty nrx.db. To add to the confusion, I
thought:

  A a = B(x);

was equivalent to:

  A a(B(x));

is my C++ really that rusty?

-- bjorn
(running XP/VC6)