[C++-sig] Problem using wrapped void* in Python
Kor de Jong
k.dejong at geog.uu.nl
Mon Dec 1 09:38:49 CET 2003
Hi Ralf,
Thank you for your reply.
Ralf W. Grosse-Kunstleve wrote:
>>So, what I am looking for is a way to tell Boost.Python how to convert
>>from void* to Python and back. I have tried various things, like the
>>opaque_pointer_converter and the to_python_converter, but I end up with
>>code which I don't understand anymore and/or which doesn't compile. I
>>would be very grateful if one of you could provide me with a bit of code
>>to get me going again.
>
>
> Recently Niall Douglas added this to the Boost.Python FAQ:
>
> http://cci.lbl.gov/~rwgk/shortcuts/boost/libs/python/doc/v2/faq.html#voidptr
>
> Does this help in your case?
I see how this works in the case of converting void* function arguments.
This will be useful for me too. But in my current case I am wrapping a
struct which has a void* datamember. Accessing the enum/int/string
datamembers of the struct from Python goes fine, but accessing the void*
datamember is a problem and gives:
TypeError: No to_python (by-value) converter found for C++ type: Pv
Again, I don't want to access the actual data pointed to by the pointer,
I just want to pass it along to wrapped functions.
I might be missing something obvious, but the docs and mailinglist
archives didn't help me further.
Does anyone have something to say about converting void* to Python and back?
Thanks,
Kor
More information about the Cplusplus-sig
mailing list