[C++-sig] return value policy for returning same python object...
milind_patil at hotmail.com
Sun Jun 8 19:59:15 CEST 2003
I have a scenario where a C++ method that performs inplace
operation on the object is wrapped using boost python. I
would like the corresponding python operation to result in the same object
instead of a new python object. What is the return policy that
will allow me to do that?
eg. in Y_Wrapper class of some Y class...
do_iadd (int other)
*this += Y_FromInt(other);
.def("__iadd__", (const Y& Y_Wrapper::*) &do_iadd(int),
return_value_policy<>(??? which one ???))
x = y.hello(0)
a = x
x += 1
assert( a is x)
I tried return_existing_object and the copy_... policies. Obviuosly, because
they all return a new python
object, that failed. Any pointers as to how I can get the desired behaviour?
(Notice I cannot do
.def (self += other<int>())
because there is no += in the Y class for Y& and int defined.)
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