[C++-sig] Re: instantiating python objects within C++
dave at boost-consulting.com
Mon May 26 20:44:32 CEST 2003
Stefan Seefeld <seefeld at sympatico.ca> writes:
> Hi David,
> David Abrahams wrote:
>> object FooClass
>> = class_<Foo>("Foo", init<int, char const*>())
>> .def( ... )
>> object foo = FooClass(3, "hello");
>> Joel, we might want to do that example in two steps as shown above
>> just to make it crystal clear what's happening.
> yes, the 'missing link' was that I didn't understand what the above
> really meant for the python interpreter.
The interpreter, if you mean the thing that executes Python
bytecodes, isn't running this at all.
> For example right now I'm not even instantiating that class
> explicitely, I use a callable's '()' operator.
> The python interpreter then figures out that it should create the so
> defined wrapper object and wrap it around my existing foo instance.
It's not really clear to me just what you mean.
> That is something I didn't understand (and still don't in detail).
> Explaining that in greater detail would surely help, not only to use
> boost.python, but also to understand how all the magic works.
Hmm. Well, yeah, a description of the conversion mechanisms would be
good to have. I've been meaning to write one for a while.
Unfortunately, most of my time is currently being taken by other
(paying) work, and it's hard to justify giving that project priority
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