[C++-sig] wrapping a function that takes a void*
Matthew Scouten
matthew.scouten at gmail.com
Fri Oct 12 18:18:30 CEST 2007
I am wraping a function that takes a void* as an argument.
class Special
{
int fooRequest(void * userData = NULL);
virtual void fooCallback(void * userData)
}
The intention is that the user data pointer will be returned to
'remind' the program what callback goes with what request.
my first attempt:
struct Special_wrapper: Special, wrapper<Special>
{
int fooRequest(PyObject * userData = NULL);
}
int Special_wrapper::fooRequest(PyObject * userData)
{
return fooRequest((void*) userData)
}
and later
class<Special_wrapper>("Special")
.def("fooRequest" ,&Special_wrapper::fooRequest ,(arg("userData") =
(void*)NULL))
I get a error the first line of which is:
C:\Documents and
Settings\mscouten\Desktop\boost_1_32_0\boost_1_32_0\boost/python/converter/arg_to_python.hpp(181)
: error C2027: use of undefined type
'boost::python::converter::detail::cannot_convert_raw_PyObject<T>'
(Full error text available on request)
Does any body have any recommendations about how I could wrap this.
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