[C++-sig] How to officially wrap a pointer into boost::python::object?
meine at informatik.uni-hamburg.de
Mon Jun 2 16:42:50 CEST 2008
This seems to be such a simple task: Given a (e.g factory) function that
wants to return a new object as boost::python::object, what is the correct
Foo *result = new Foo();
boost::python::object pyresult = ..... result .....; // <- PLEASE FILL IN
// e.g. set python attribute on pyresult..
As far as I know, something like this was in the tutorial in the past, but has
been deleted without being reproduced in any other place I know of.
What I am doing right now is a little bit clumsy:
boost::python::object pyresult =
boost::python::detail::new_reference( // ugly: private/"detail" API
I have looked at the implementation of manage_new_object to find a nicer
shortcut, which leads to a is_polymorphic-if branch using
detail::wrapper_base_::owner or detail::make_owning_holder respectively.
I refrained from using make_owning_holder directly, not only because it is
also in the detail namespace, but also because of the second if-branch which
I completely do not understand.
Also, I would like to not take the detour via an intermediate PyObject * which
has to be wrapped again; make_owning_holder suggests that using std::auto_ptr
could be a way, but I am unsure if this works with the special-cased Intel5
and VC 6 Dinkum library and whether I may leave out the above is_polymorphic
In the end, I would like to know
a) what is the right way(tm) for common end users,
b) where this is (prominently) documented, and
c) what is the perfectly-fine-in-all-cases way for code that should eventually
go into the BPL.
Ciao, / /
/ / ANS
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