[C++-sig] functools.partial vs boost::python
troy d. straszheim
troy at resophonic.com
Thu Dec 3 19:07:55 CET 2009
Neal Becker wrote:
> Has anyone noticed that a function created with boost::python using
> args() to give keyword arguments doesn't seem to work with
> functools.partial keyword arguments (but does with positional args)?
>
> For example, I have this function:
> class_<boost_uniform_real_wrap>
> ("uniform_real", "Uniform float distribution",
> bp::init<rng_t&,double,double>(
> (bp::arg ("rng"),
> bp::arg ("min"),
> bp::arg ("max"))...
>
> Then:
> from functools import partial
> f = partial (uniform_real, rng=rng1) << using keyword doesn't work
> f (1,2)
> ArgumentError: Python argument types in
> uniform_real.__init__(uniform_real, int, int)
> did not match C++ signature:
> __init__(_object*, boost::random::mersenne_twister<unsigned int,
> 32, 624, 397, 31, 2567483615u, 11, 7, 2636928640u, 15, 4022730752u,
> 18, 3346425566u> {lvalue} rng, double min, double max)
>
> But this works:
> from functools import partial
> f = partial (uniform_real, rng1) << pos arg does work
>
> In [27]: f(1,2)
> Out[27]: uniform_real(1,2)
>
That doesn't work for pure python functions either:
>>> def f(x,y,z): return x*100 + y*10 + z
...
>>> from functools import partial as p
>>> p(f,x=1)(2,3)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: f() got multiple values for keyword argument 'x'
>>> p(f,x=1)(y=2,z=3)
123
>>> p(f,1)(2,3)
123
The error message is misleading for sure. Boost.python is going through
a list of overloads and trying them in order; if it runs out of
overloads, it says nothing matched. I think I can get it to be smarter
about this, lemme see...
-t
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