[C++-sig] Converintg C++ object to python object

[Jadhav, Alok]

When I pass a C++ object to Python function, I want to be able to use
that object using its Proxy class in the python code. How can I achieve
that?

Regards, Alok

 

-----Original Message-----
From: cplusplus-sig-bounces+alok.jadhav=credit-suisse.com at python.org
[mailto:cplusplus-sig-bounces+alok.jadhav=credit-suisse.com at python.org]
On Behalf Of Jadhav, Alok
Sent: Wednesday, December 09, 2009 10:13 AM
To: Development of Python/C++ integration
Subject: [C++-sig] Converintg C++ object to python object

In my C++ callback function below

[code]

static void PythonCallBack(RFAMessage *msg, void *clientdata) {
   PyObject *func, *arglist;
   PyGILState_STATE state; 
   state = PyGILState_Ensure();
   func = (PyObject *) clientdata;               // Get Python function
   RFAMessageWrapper msg2(msg);
 
   PyObject *argobj = SWIG_NewPointerObj(SWIG_as_voidptr(&msg2),
SWIGTYPE_p_RFAMessageWrapper , SWIG_POINTER_NEW |  0 );
  
   arglist = Py_BuildValue("(O)",argobj);             // Build argument
list
   PyEval_CallObject(func,arglist);     // Call Python
  Py_XDECREF(arglist);                           // Trash arglist
   //SWIG_PYTHON_THREAD_END_BLOCK;
   PyGILState_Release(state);
}

[/code]

Can you tell me if the usage of  SWIG_NewPointerObj is correct? I want
to convert a C++ class object into python equivalent object. In the
python code, the passed object is identified as SwigPyObject and not
RFAMessageWrapper which I am expecting.

How can I convert RFAMessageWrapper object into its Python equivalent to
that in my Python function I can use the passed object as
RFAMessageWrapper.

Regards,
Alok

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