[C++-sig] Py++ module for code with protected operator=

Maciej Sitarz macieksitarz at wp.pl
Fri Mar 19 17:42:40 CET 2010

Hi all,

I want to create python module for class that has protected operator=.
That class placed in std::vector and code generated by Py++ uses that 

Simple example...
The c++ code:

#include <vector>

class JobPropertyWrapper {
                 JobPropertyWrapper& operator=( const 
JobPropertyWrapper& aProp ) throw () { return *this; }

class classA {
                 void fun( const std::vector<JobPropertyWrapper>& v) { }

int main() {
         classA c;
         c.fun( std::vector<JobPropertyWrapper>() );
         return 1;

Py++ script:

mb = module_builder.module_builder_t( ... )
mb.class_( 'JobPropertyWrapper' ).noncopyable = True
mb.build_code_creator( module_name='test' )

The compile error(part of it):

test.h:6: error: 'JobPropertyWrapper& 
JobPropertyWrapper::operator=(const JobPropertyWrapper&)' is protected
error: within this context
test.h: In member function 'void std::vector<_Tp, 
std::_Vector_base<_Tp, _Alloc>::_Tp_alloc_type::pointer, 
std::vector<_Tp, _Alloc> >, const _Tp&) [with _Tp = JobPropertyWrapper, 
_Alloc = std::allocator<JobPropertyWrapper>]':

As you can see i tried to inform py++ that the class is 'noncopyable' 
but that didn't do the trick.

I attached the generated code.
There's also some problem with operator== not existing, which I also 
didn't know how to fix.

Thanks in advance
Maciek Sitarz

Maciek Sitarz
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