[docs] [issue19933] Round default argument for "ndigits"

João Bernardo report at bugs.python.org
Mon Dec 9 05:24:20 CET 2013

New submission from João Bernardo:

>From the docs for built-in function "round":
   "If ndigits is omitted, it defaults to zero"

But, the only way to get an integer from `round` is by not having the second argument (ndigits):

    >>> round(3.5)
    >>> round(3.5, 1)
    >>> round(3.5, 0)
    >>> round(3.5, -1)
    >>> round(3.5, None)
    Traceback (most recent call last):
      File "<pyshell#6>", line 1, in <module>
        round(3.5, None)
    TypeError: 'NoneType' object cannot be interpreted as an integer

Either the docs are wrong or the behavior is wrong. I think it's easier to fix the former...

But also there should be a way to make round return an integer (e.g. passing `None` as 2nd argument)

assignee: docs at python
components: Documentation, Interpreter Core
messages: 205647
nosy: JBernardo, docs at python
priority: normal
severity: normal
status: open
title: Round default argument for "ndigits"
versions: Python 3.4

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