[docs] [issue22052] Comparison operators called in reverse order for subclasses with no override.

[Mark Dickinson]

Mark Dickinson added the comment:

> "the subclass provides" doesn't actually imply anything about overriding, I think.

Yes, that was the thrust of one of the SO answers.  Unfortunately, that explanation doesn't work for arithmetic operators, though: there an explicit override is necessary.  Here's another example, partly to get away from the extra complication of __eq__ being its own inverse.  After:

    class A(object):
        def __lt__(self, other): return True
        def __gt__(self, other): return False
        def __add__(self, other): return 1729
        def __radd__(self, other): return 42

    class B(A): pass

we get:

    >>> A() + B()
    1729
    >>> A() < B()
    False

So the addition is calling the usual __add__ method first (the special exception in the docs doesn't apply: while B *is* a subclass of A, it doesn't *override* A's __radd__ method).  But the comparison is (surprisingly) calling the __gt__ method first.

So we've got two different rules being followed: one for arithmetic operators, and a different one for comparisons.

This isn't a big deal behaviour-wise: I'm certainly not advocating a behaviour change here.  But it would be nice to document it.

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<http://bugs.python.org/issue22052>
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