[Flask] Serving a file to downalod AND print message on screen

Wed Nov 22 12:24:29 EST 2017

Thanks UB.

This URL explains how to upload file. For allowing users to download result (which I want), it uses send_from_directory function as a return statement.
This prevents me from printing information on the screen before download.

As I found out, I can render the information to be printed through a template html file wherein I also provide a link to download the file.

My template html has code like:

"Download result <a href=/static/results.zip>here</a>
Other information goes here...
"

Thanks,
Abhinav

On Nov 22, 2017, at 5:07 AM, Ulrich Berthold <ub at artfacts.net<mailto:ub at artfacts.net>> wrote:

hey abhinav,

On Tue, Nov 21, 2017 at 07:30:02PM +0000, Kumar, Abhinav wrote:
Thanks for your thoughts.

I can serve the file if I put it in 'static' folder, but not in 'upload' folder.
I guess 'static' is exposed by default.
I am not sure how to expose any other folder like 'upload'.
did you have a look at the fileupload pattern?
http://flask.pocoo.org/docs/0.12/patterns/fileuploads/

it does exactly what you want, upload a file to a configurable upload
folder and consequently serve the file from that location.

hope that helps .. all the best,
ub

Thanks,
Abhinav

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From: Flask [flask-bounces+akumar=intrexon.com at python.org<mailto:flask-bounces+akumar=intrexon.com at python.org>] on behalf of sidwoodstock . [sidwoodstock at gmail.com<mailto:sidwoodstock at gmail.com>]
Sent: Tuesday, November 21, 2017 9:35 AM
To: flask at python.org<mailto:flask at python.org>
Subject: Re: [Flask] Serving a file to downalod AND print message on screen

Just some thoughts:

- Verify file is truly placed in /uploads/
- Verify your file server is exposing your uploads directory.
- You can move around the code in your template which shows flashed messages, perhaps move it to a place which gets called when you want.

To truly help with the uploads / file not found issue, it'd be helpful to know what other packages you're using.

Scott Woodstock

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Today's Topics:

  1. Re: Serving a file to downalod AND print message on screen
     (Geert Stappers)

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Date: Thu, 16 Nov 2017 21:16:10 +0100
From: Geert Stappers <stappers at stappers.nl<mailto:stappers at stappers.nl><mailto:stappers at stappers.nl>>
To: flask at python.org<mailto:flask at python.org><mailto:flask at python.org>
Subject: Re: [Flask] Serving a file to downalod AND print message on
       screen
Message-ID: <20171116201610.GX21385 at gpm.stappers.nl<mailto:20171116201610.GX21385 at gpm.stappers.nl><mailto:20171116201610.GX21385 at gpm.stappers.nl>>
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On Wed, Nov 15, 2017 at 05:47:19PM +0000, Kumar, Abhinav wrote:
Hi,

After I process some data, I want to write log output to the screen and let user download the results as a zip file.

I tried flash, but that does not print message until the app is executed next time.

I can't possible use two return statements (one for send_file for download and other for rendering a template).

I could use only template rendering and provide a link to download the results file in the template html file, but that link says 'file not found'...

In my template file I have code like
   Please download the result  <a href=/upload/results.zip>here</a>
And I place the results.zip file in "upload" folder before calling render_template.

But the app says "The requested URL was not found on the server"
The URL it points to is "http://akumar-linux2:5000/upload/results.zip"

FWIW   I read above _two_ problems:
* URL not found
* wanting to write to screen

Advice: Start with fixing the "URL not found".

Groeten
Geert Stappers
Seen both postings from original poster, replying on one.
--
Leven en laten leven

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