[IPython-dev] help with @interactive
Mark Bakker
markbak at gmail.com
Sun Jan 19 16:18:18 EST 2014
Hello List,
I am trying to do this (got this from one of Fernando's Notebooks):
@interactive( x=(0,10) )
def f(x):
print 'x is: ',x
But I get an error:
TypeError: interactive() got an unexpected keyword argument 'x'
Any thoughts? I am running 1.0.0-2
Thanks,
Mark
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