[IPython-dev] Accessing get_ipython() within an embedded shell
takowl at gmail.com
Tue Apr 10 15:18:04 EDT 2018
On this topic, it bears reiterate that 'embedding' IPython has a specific
purpose: to run IPython with the namespace where it was called, like a
debugger with no stepping forwards.
If you want to run IPython programmatically with its own namespace, you
don't need to 'embed' it, and embedding has extra complexities that might
confuse things. You can still access the namespace of a regular IPython
shell object as ip.user_ns .
On 10 April 2018 at 20:41, Jacob Vanderplas <jakevdp at cs.washington.edu>
> Thanks for the links! I found the clue I needed in the pytest-ipdb link.
> Instead of using:
> from IPython.terminal.embed import InteractiveShellEmbed
> ipshell = InteractiveShellEmbed()
> I used this:
> from IPython import InteractiveShell
> ipshell = InteractiveShell.instance()
> And now calls to IPython.get_ipython() within the shell work properly.
> Jake VanderPlas
> Senior Data Science Fellow
> Director of Open Software
> University of Washington eScience Institute
> On Tue, Apr 10, 2018 at 2:22 AM, Wes Turner <wes.turner at gmail.com> wrote:
>> ipdb or pytest-ipdb may have a helpful example?
>> These all require nose:
>> On Tuesday, April 10, 2018, Jacob Vanderplas <jakevdp at cs.washington.edu>
>>> I'm trying to create automated tests for some magic functions within a
>>> pytest framework. I've figured out how to do part of what I need using
>>> an embedded interactive shell; briefly, I do something like this:
>>> from IPython.terminal.embed import InteractiveShellEmbed
>>> ipshell = InteractiveShellEmbed()
>>> out = ipshell.run_cell("%my_magic_command")
>>> assert out.result == expected_result
>>> The problem I encounter is that my magic function optionally uses
>>> IPython.get_ipython().user_ns to access variables in the user
>>> namespace, and IPython.get_ipython() returns None when run within an
>>> embedded shell in this way.
>>> Is there a way to create a simple embedded shell like this one that will
>>> behave as if it is an actual IPython shell, with IPython.get_ipython()
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