[Mailman-Developers] How To change queue process method

[Maickel Pandie]

Hi friend....

Do you have any suggestion what SMTP benchmark I can use except
Multimail2 to test Mailman+Postfix? Something that can return some
variabel not only sending a lot of email ?(This is for research and
not for spamming other)

Thanks

2008/6/19 Maickel Pandie <maickel.pandie at gmail.com>:
> I'm sory, but I have to do this research.
> There is a case:
> a lot of people using mailing list server to distribute many kind of
> file to their group. The important things are a lot of group using
> mailing list to distribute a big file but not urgent such as big
> resolution picture, movie, etc. there also a group using mailing list
> for work like distributing their report(pdf, doc, odt (small file))
> and they need it to be delivered fast. The bandwidth is not so big to
> deliver a lot of big file fast so I'm doing this research. This is my
> kind of job now to research something like this despite this is not
> important but I have to do it and make the report for the result.
>
> Thanks for your help
>
> 2008/6/18 Mark Sapiro <mark at msapiro.net>:
>> Maickel Pandie wrote:
>>>
>>>1. Can you give me the example of dequeue metadata file to get the
>>>listname of the message please? I need the listname of the message
>>>because I made my own function to count how many domain as the
>>>destination of the message and the input of that function is listname
>>
>>
>> You are creating a huge can of worms, however if you insist ...
>>
>> In the files() method, you don't want to dequeue the message because
>> while that will get you the message and the metadata, it will also
>> remove the queue entry (actually rename it from .pck to .bak). I
>> suppose you could then rename the .bak back to .pck, but since files()
>> is really only in the business of preparing a list of entries to be
>> dequeued by a runner, I think it is best to read the pickle (if you
>> must) without dequeueing it in the files() method.
>>
>> So you would do something like:
>>
>>    msg = cPickle.load(fp)
>>    data = cPickle.load(fp)
>>
>> Then the list name is data.get('listname')
>>
>>>2. Can you give me any suggestion how to get attachment file size from
>>>each message?
>>
>>
>> You can look at the "Is the message too big?" code in
>> Mailman/Handlers/Hold.py.
>>
>>
>>>3. Is there any function in mailman who can give me the size of the
>>>message? What variable that I need to get the size of the message?
>>>(filename, listname, filebase, or other variabel)
>>
>>
>> With msg and data as above
>>
>>    if data.get('_parsemsg'):
>>        size = len(msg)
>>    else:
>>        size = len(msg.as_string())
>>
>>
>> Ask yourself if the cost of all this extra work is not greater than
>> whatever you think you're going to save.
>>
>> --
>> Mark Sapiro <mark at msapiro.net>        The highway is for gamblers,
>> San Francisco Bay Area, California    better use your sense - B. Dylan
>>
>>
>