[Mailman-Users] --with-mail-gid=?

[Hennie Rautenbach]

Hi there folks,

I have downloaded/configured/compiled and installed mailman-2.0.13 on a 
Sun running Solaris 8 and Python 2.2.1 and sendmail 8.10.2.

I have followed the documentation as best I could and have setup a 
mailing list etc.

When I post to the list the following error appear in /var/log/syslog...

Oct 23 10:14:44 vogue sendmail[15676]: [ID 801593 mail.info] 
g9NAEev15676: from=
<hennie at sabinet.co.za>, size=1600, class=0, nrcpts=1, 
msgid=<3DB65A82.7040903 at sa
binet.co.za>, proto=ESMTP, daemon=MTA, relay=mfwjs01.mfw.is.co.za 
[196.35.77.13]
Oct 23 10:14:44 vogue Mailman mail-wrapper: [ID 702911 mail.error] 
Failure to ex
ec script. WANTED gid 2, GOT gid 1.  (Reconfigure to take 1?)

So my (probably stupid) question is: How do I determine under which GID 
sendmail runs ?

Regards,

Hennie

-- 
===================================================================
 Hennie Rautenbach                  Work: http://www.sabinet.co.za
 082-556-1191                       Play: http://www.overland.co.za	

 It's choice, not chance, that determines your destiny. 
                                       -- Jean Nidetch
 ===================================================================



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