[Matplotlib-users] Why the V parameter in matplotlib.axes.Axes.contour must be increasing?
Jody Klymak
jklymak at uvic.ca
Wed Aug 16 12:48:37 EDT 2017
Hi David,
I’ve definitely run into this, to my annoyance.
Do you think you can open an issue on
[GitHub](https://github.com/matplotlib/matplotlib/issues)? If you
don’t want to, I’m happy to do it.
With respect to one contour at zero, its easier than Matlab:
ax.contour(X, np.array([0.]))
works for me…
Cheers,
On 16 Aug 2017, at 5:33, Xi Shen wrote:
> Hi,
>
> https://matplotlib.org/api/_as_gen/matplotlib.axes.Axes.contour.html
> says
> the contour function accept a vector parameter V which must be in
> increasing value. But the contour function in MATLAB does not have
> this
> restriction.
>
> I understand the underlining implementation of these two functions
> could be
> very different. I want to understand what is the purpose of this
> restriction, and if it possible to create a contour image the same as
> MATLAB does by using contour with V = [0 0]?
>
>
> Regards,
> David
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