[PYTHON MATRIX-SIG] More repr vs. str issues - Please Read!

[Perry A. Stoll]

> The problem with the current repr function is that it doesn't display the 
> internal structure of the array which leaves out a lot of valuable 
> information.  To fix all of these problems in one fell swoop ;-), I propose 
> the following new behavior:
> 
>>>> from Numeric import *
>>>> a = identity(10)
>>>> a # same as repr(a)
> array([[1, 0, 0, 0, 0, 0, 0, 0, 0, 0],
>        [0, 1, 0, 0, 0, 0, 0, 0, 0, 0],
>        [0, 0, 1, 0, 0, 0, 0, 0, 0, 0],
>        [0, 0, 0, 1, 0, 0, 0, 0, 0, 0],
>        [0, 0, 0, 0, 1, 0, 0, 0, 0, 0],
>        [0, 0, 0, 0, 0, 1, 0, 0, 0, 0],
>        [0, 0, 0, 0, 0, 0, 1, 0, 0, 0],
>        [0, 0, 0, 0, 0, 0, 0, 1, 0, 0],
>        [0, 0, 0, 0, 0, 0, 0, 0, 1, 0],
>        [0, 0, 0, 0, 0, 0, 0, 0, 0, 1]], 'l')

Will repr format it as above, i.e. including the newlines? Currently
it returns a single string without newlines, basically nullifying an
easy scan of the internal structure. 

# currently, repr does this: 
>>> repr(a)
"array([[1, 0, 0, 0, 0, 0, 0, 0, 0, 0], [0, 1, 0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 1, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 1, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 1, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 1, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 1, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0, 1, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0, 1, 0], [0, 0, 0, 0, 0, 0, 0, 0, 0, 1]], 'l')"

-Perry



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